Actually, this answer would be true. Why?
The first equation is: a(sub <em>n</em>) = 8, 13, 18, 23
The second is: a(sub 1)=8 ; a(sub <em>n</em>)= a(sub <em>n</em>-1)+5
if you wish to find the second term, plug two into the equation for <em /><em>n</em>
8+5=13
to find the third, plug the second term, 13, in for <em>n.</em>
13+5=18.
Hope this helped! I know it's a bit on the late side, but at least you can get the general idea!
7- 5n=6+6(n+2)
7- 5n=6+6n+12
7 -5n=18+6n
5n-6n=18-7
-11n=11
n=-1
Answer:
I don't how to do this but check Quizlet♂️
After demonstrating the procedure by algebraic means, the expression ![(2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} )](https://tex.z-dn.net/?f=%282%5Csqrt%5B3%5D%7B12%7D%20%29%5Ccdot%20%283%5Csqrt%5B3%5D%7B2%7D%20%29)
<em>is equivalent to</em> ![6\cdot \sqrt[3]{24}](https://tex.z-dn.net/?f=6%5Ccdot%20%5Csqrt%5B3%5D%7B24%7D)
.
In this question we proceed to <em>simplify</em> by <em>algebraic</em> means into a <em>single</em> <em>radical</em> expression when possible, whose procedure is shown below and explained by appropriate definitions and theorems:
- Given.
-
![(2\cdot 3) \cdot (\sqrt[3]{12} \cdot \sqrt[3]{2} )](https://tex.z-dn.net/?f=%282%5Ccdot%203%29%20%5Ccdot%20%28%5Csqrt%5B3%5D%7B12%7D%20%5Ccdot%20%5Csqrt%5B3%5D%7B2%7D%20%20%29)
Commutative property/ Associative property. - Definition of cubic root/
![\sqrt[n]{a} = \sqrt[n]{b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%3D%20%5Csqrt%5Bn%5D%7Bb%7D)
/Result
After demonstrating the procedure by algebraic means, the expression <em>is equivalent to</em> .
To learn more on radical expressions, we kindly invite to check this verified question: brainly.com/question/1810591
