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sweet-ann [11.9K]
3 years ago
15

Cameron rent is 2,308 per month and wants to pay rent in $100 dollar bills and $1 dollar bills. How many $100 dollar bills will

Cameron need to pay his tent for ten months?
Mathematics
2 answers:
posledela3 years ago
8 0
$2,000 = 20 $100 dollar bills
20 (hundred dollar bills)*10 (months) = 200 $100 dollar bills
2,300-2,000 =3(hundred dollar bills)*10(months) = 30 $100 dollar bills
200+30 =230
The answer is, Cameron will need 230 $100 dollar bills to pay his rent for ten months.
Hope this helps
Alinara [238K]3 years ago
6 0
(2308*10)/100=230.3 so he would have to pay 230 hundos (and 30 singles)
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<u>Convert minutes and seconds to minutes:</u>
\text{3 mins 45 seconds} \longrightarrow 3 \dfrac{3}{4} \text{mins}


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\text{1 min} \longrightarrow 28 \text{ copies}

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3 years ago
Decrease 40 by 15%<br><br> please explain how you got your answer too :)
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Suppose the number of radios in a household has a binomial distribution with parameters n=11 and p=40%. Find the probability of
Ivenika [448]

Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x=r) = nCr × q^(n-r) × p^r

From the information given,

n = 11

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q = 1 - 0.4 = 0.6

x represent the number of radios

a) P( x = 1) or P(x = 9)

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P(x = 1) = 0.027

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P( x = 1) or P(x = 9) = 0.027 + 0.0052 = 0.0322

b) P(x lesser than or equal to 7) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5) + P(x = 6)

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P(x = 1) = 0.027

P(x = 2) = 11C2 × 0.6^(11-2) × 0.4^2 = 0.089

P(x = 3) = 11C3 × 0.6^(11-3) × 0.4^3 = 0.177

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P(x = 5) = 11C5 × 0.6^(11-5) × 0.4^5 = 0.22

P(x = 6) = 11C6 × 0.6^(11-6) × 0.4^6 = 0.15

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d) P(x lesser than 9) = P(x lesser than or equal to 7) + P(x = 8)

P(x = 8) = 11C8 × 0.6^(11-8) × 0.4^8 = 0.02

P(x lesser than 9) = 0.977 + 0.02 = 0.997

e. P(x greater than 7) = 1 - P(x lesser than or equal to 7) = 1 - 0.977 = 0.023

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