The answer is 4/10*cos 01
13 : 7
(as eli has seven
and his dister has 6 more therefore 6+7 =13)
so this must be the correct answer
hope it will help you
Answer: " (3,1) is the point that is halfway between <em>A</em> and <em>B</em>. "
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Explanation:
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We know that there is a "straight line segment" along the y-axis between
"point A" and "point B" ; since, we are given that:
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1) Points A, B, C, and D form a rectangle; AND:
2) We are given the coordinates for each of the 4 (FOUR points); AND:
3) The coordinates of "Point A" (3,4) and "Point B" (3, -2) ; have the same "x-coordinate" value.
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We are asked to find the point that is "half-way" between A and B.
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We know that the x-coordinate of this "half-way" point is three.
We can look at the "y-coordinates" of BOTH "Point A" and "Point B".
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which are "4" and "-2", respectively.
Now, let us determine the MAGNITUDE of the number of points along the "y-axis" between "y = 4" and y = -2 .
The answer is: "6" ; since, from y = -2 to 0 , there are 2 points, or 2 "units" from y = -2 to y = 0 ; then, from y = 0 to y = 4, there are 4 points, or 4 "units".
Adding these together, 2 + 4 = 6 units.
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So, the "half-way" point would be 1/2 of 6 units, or 3 units.
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So, from y = -2 to y = 4 ; we could count 3 units between these points, along the "y-axis". Note, we could count "2" units from "y = -2" to "y = 0".
Then we could count one more unit, for a total of 3 units; from y = 0 to y = 1; and that would be the answer (y-coordinate of the point).
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Alternately, or to check this answer, we could determine the "halfway" point along the "y-axis" from "y = 4" to "y = -2" ; by counting 3 units along the "y-axis" ; starting starting with "y = 4" ; note: 4 - 3 = 1 ; which is the "y-coordinate" of our answer; that is: "y = 1" ; and the same y-coordinate we have from the previous (aforementioned) method above.
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We know the "x-coordinate" is "3" ; so the answer:
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" (3,1) is the point that is halfway between <em>A</em> and<em> B </em>."
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Answer:
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Step-by-step explanation:
