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3 years ago

Kira keeps track of how much time she spends walking her dog each morning. Her data

Mathematics

2 answers:

NemiM [27]3 years ago

8 0

Answer:18 minutes

Step-by-step explanation:

You have to subtract the numbers from the end from each other and u get the range wh i.c h is18

lorasvet [3.4K]3 years ago

5 0

Answer:

18 mins

Step-by-step explanation:

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I will award branliest Translate from binary to decimal: a) 11₂ b) 111₂

Kryger [21]

The answer is

1) 3

2) 7

since each place value is different from base 10

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3 years ago

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Xavier has x dollars. This morning Alex had twice as much money as Xavier. After Alex spent three dollars on chips, he only had

sweet [91]

Answer:

Xavier has 5 dollars

Step-by-step explanation:

2x represents how much money Alex had, the -3 is how much he spent, and the 7 is how much he has now

$2x-3=7$

Add 3 to both sides

$2x=10$

divide both sides by 2

$x=5$

Checking my work:

$2*5-3=7\\10-3=7\\7=7$

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3 years ago

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Zolol [24]

Answer:

Step-by-step explanation:

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3 years ago

HELP PLEASE! Solve for m. 3.6m = 14.4

Alekssandra [29.7K]

Answer:

Step-by-step explanation:

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3 years ago

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A, B and C are events such that P(A) = 1/3, P(B) = ¼, and P(C) = 1/5. Find P(AUBUC) under each of the following assumptions: a)

marta [7]

(a) If $A,B,C$ are mutually exclusive, then

$P(A\cap B)=P(A\cap C)=P(B\cap C)=P(A\cap B\cap C)=0$

so we have

$P(A\cup B\cup C)=P(A)+P(B)+P(C)=\dfrac{47}{60}$

(b) If $A,B,C$ are mutually independent, then

$P(A\cap B)=P(A)P(B),$

$P(A\cap C)=P(A)P(C),$

$P(B\cap C)=P(B)P(C),$

$P(A\cap B\cap C)=P(A)P(B)P(C)$

so that

$P(A\cup B\cup C)=P(A)+P(B)+P(C)-(P(A\cap B)+P(A\cap B)+P(B\cap C))+P(A\cap B\cap C)$

$P(A\cup B\cup C)=\dfrac{47}{60}-\left(\dfrac1{12}+\dfrac1{15}+\dfrac1{20}\right)+\dfrac1{60}$

$P(A\cup B\cup C)=\dfrac35$

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4 years ago