<u>Hint </u><u>:</u><u>-</u>
- To find out the equation of the line we can use the point slope form of the line which is
<u>Solution</u><u> </u><u>:</u><u>-</u>
The given point to us is ,
and the slope of the line is 4 . On using the point slope form , we have ,
<u>Hence</u><u> the</u><u> </u><u>equation</u><u> </u><u>is </u><u>4</u><u>x</u><u> </u><u>-</u><u> </u><u>y </u><u>+</u><u> </u><u>3</u><u> </u><u>=</u><u> </u><u>0</u><u> </u>
( for graph , see attachment ) .
Answer:
i dont know
Step-by-step explanation:
But can you just like it cause im trying get enough points to be able have a hundred points so i could have help with a college essay
please
Hello there!
The point (2,-3) would lay in quadrant IV, or 4.
Basically:
Points that are (x, y) or positive x and positive y ay in quadrant 1, or I.
Points that are (-x, y) or negative x and positive y lay in quadrant 2, or II.
Points that are (-x, -y) or negative x and negative y usually lay in quadrant 3, or III.
Points that are (x, -y) or positive x and negative y usually lay in quadrant 4, or IV.
I hope this was helpful! Have a great rest of your day :)