Given:
The quadratic equation is
To find:
The x-intercepts of the given equation.
Solution:
We have,
Splitting the middle term, we get
For x-intercepts, y=0.
Using zero product property, we get
So, the x-intercepts are (0.5,0) and (2,0).
Therefore, the correct option is a.
Greater than because they are negative
<span>We have to use PEMDAS for this expression.
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction
</span>(2x^2 - 5x + 4) Original Mathematical Expression
[2(7)^2 - 5(7) + 4] Plugging the value of x, 7 into expression.
There are parentheses, so that means we have to work in them.
There are exponents, so we have to do those first.
[2(49) - 5(7) +4] Exponents.
There is multiplication, that we can do, so we do that left to right.
[98 - 35 + 4] Multiplication.
There is no division.
There is addition and subtraction, so we do those left to right.
[63 + 4] Subtraction.
67 Addition.
Final Answer: 67
Explanation:
a. The line joining the midpoints of the parallel bases is perpendicular to both of them. It is the line of symmetry for the trapezoid. This means the angles and sides on one side of that line of symmetry are congruent to the corresponding angles and sides on the other side of the line. The diagonals are the same length.
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b. We observe that adjacent pairs of points have the same x-coordinate, so are on vertical lines, which have undefined slope. KN is a segment of the line x=1; LM is a segment of the line x=3. If the trapezoid is isosceles, the midpoints of these segments will be on a horizontal line. The midpoint of KN is at y=(3-2)/2 = 1/2. The midpoint of LM is at y=(1+0)/2 = 1/2. These points are on the same horizontal line, so the trapezoid <em>is isosceles</em>.
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c. We observed in part (b) that the parallel sides are KN and LM. The coordinate difference between K and L is (1, 3) -(3, 1) = (-2, 2). That is, segment KL is the hypotenuse of an isosceles right triangle with side lengths 2, so the lengths of KL and MN are both 2√2.
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For part (c), we used the shortcut that the hypotenuse of an isosceles right triangle is √2 times the leg length.
The distance is approximately 703 kilometers.
To travel that in 12 hours, a car has to go at 703/12=58.583 km/h