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3 years ago

It is attached please help! Why is it c?

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

6 0

The answer is B.
The total hours worked is 5 x 8 teams is 40 hours x 2 cars per hour is 80 cars.
$600/80= $7.50 per car

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X/10 = 2 Solve for x x = ?

Montano1993 [528]

Answer:

20 ÷ 10 = 2

So x = 20

Step-by-step explanation:

Hope this helps!

8 0

3 years ago

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For every 3 dogs Carol has, she keeps 12 treats. Which is the correct rate?

Tems11 [23]

Answer:

4 treats per dog.

Step-by-step explanation:

Find the rate that she keeps for one dog. As it gives you the rate for 3 dogs, simply divide 3:

(3 dogs/12 treats)/(3/3) = (1 dog/4 treats).

Carol keeps 4 treats for every dog she has.

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3 years ago

Give the opposite of each number. a. 3 b. –9 c. –5 d. 12

inessss [21]

Opposites:
a. -3
b. 9
c. 5
d. -12

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3 years ago

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GIVE OUT BRAINLY 2) Kathleen is a sales associate in a jewelry store. She earns $560/wk plus an 8% commission on sales. How much

pashok25 [27]

Answer:

1750

Step-by-step explanation:

Earns per week: $560

Total sales per week: $x$

Weekly commission on sales: 0.08 $x$

Total Earning per week: $560 + 0.08x$

$560 + 0.08x \geqslant 700$

Simplifying this inequality:

$560 + 0.08x \geqslant 700\\0.08x \geqslant 700 - 560\\0.08x \geqslant 140\\\\x \geqslant \frac{140}{0.08}\\\\x \geqslant 1750$

Her sales must be at least $1750.

3 0

3 years ago

a farmer wants to fence in a rectangular plot of land adjacent to the north wall of his barn. no fencing is needed along the bar

xenn [34]

The constraint for the maximum enclosed area is the amount the farmer is

willing to spend on fencing.

The width of the plot that will give the most area, y = 83. $\underline{\overline 3}$ feet

The length of the plot that will give the most area, y = 125 feet

Reasons:

The given parameters are;

The cost of fencing per foot = $20

The maximum amount the farmer is willing to spend = $5000

Number of sides of fencing = 3 sides

Cost of the west side of the = Split with neighbor

Solution:

Let, y, represent the length of the fence, and let x represent the width of

the fence, we have;

Length of fence required = y + 2·x

Cost of the fence = 20·y + 20·x + (20÷2)·x = 20·y + 30·x

Therefore;

Maximum amount to be spent on the fence, 5000 = 20·y + 30·x

$\therefore y = \dfrac{5000 - 30 \cdot x}{20} = 250 - \dfrac{3}{2} \cdot x$

$y = \mathbf{250 - \dfrac{3}{2} \cdot x}$

Area of a rectangle = Length × Width

The enclosed rectangular area of the fencing, A = y × x

$\therefore A = \left(250 - \dfrac{3}{2} \cdot x\right) \cdot x = 250 \cdot x - \dfrac{3}{2} \cdot x^2$

$\therefore A = -\mathbf{ \dfrac{3}{2} \cdot x^2 + 250 \cdot x}$

The leading coefficient of the quadratic function of the area is negative,

therefore, the function only has a maximum point.

At the point of the most area, the slope, $\dfrac{dA}{dx} = 0$

Finding the value of x at the maximum point, we get;

$\dfrac{dA}{dx} = \mathbf{ \dfrac{d}{dx} \left( 250 \cdot x - \dfrac{3}{2} \cdot x^2\right)} = 250- 3 \cdot x = 0$

Therefore;

$\mathrm{ The \ width \ of \ the \ plot \ that \ will \ enclose \ the \ area}, \ x = \dfrac{250}{3} \ feet = \underline{83.\overline 3 \ feet}$

$\mathrm{ The \ length \ of \ the \ plot \ that \ will \ enclose \ the \ area}, \ y = 250 - \dfrac{3}{2} \times \dfrac{250}{3} = 125$

The length of the plot that will give the most area, y = 125 feet

Learn more here:

brainly.com/question/16337916

brainly.com/question/16545343

6 0

3 years ago