Answer:
It is 1/11
Step-by-step explanation:
Apply the rule a/c +- b/c = a+-b/c
=8-7/11
=1/11
Answer:
P = 1/(sqrt(4)) and w = 1/(sqrt(9))
Step-by-step explanation:
Only the roots of perfect squares are rational numbers. 2, 3, 6, and 10 are not perfect squares, so their roots are irrational. Both 4 and 9 are perfect squares, so their roots are rational. The sum of rational numbers is a rational number.

Answer:
<u></u>
- <u>She should aim 6 feet down the wall</u>
Explanation:
The diagram attached sketches the situtation.
Since the angle with which the ball hits the wall is the same with which it bounces, angle β is the same for the two shown triangles.
Then, since both are right triangles, then all the angles are congruent and the triangles are similar. Hence, you can equal the ratios of the sides, to make an equation:
You have other equation:
Substitute
- 2y + y = 18
- 3y = 18
- y = 18/3
- y = 6 ← this is the distance down the wall where the ball should hit
Then, she should aim 6 feet down the wall.
If the value of the z-score is 1. Then the probability that a cat will weigh less than 11 pounds will be 0.84134.
<h3>What is the z-score?</h3>
The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.
The z-score is given as
z = (x - μ) / σ
Where μ is the mean, σ is the standard deviation, and x is the sample.
The weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds.
Then the probability that a cat will weigh less than 11 pounds will be
The value of z-score will be
z = (11 – 9) / 2
z = 1
Then the probability will be
P(x < 11) = P(z < 1)
P(x < 11) = 0.84134
Thus, the probability that a cat will weigh less than 11 pounds will be 0.84134.
More about the z-score link is given below.
brainly.com/question/15016913
#SPJ1
Answer:

Step-by-step explanation:
<u>Density</u>
The density of an object of mass m and volume V is given by

It can be expressed in common units like
or any other combination of proper mass [M] by volume [V] units.
The data provided in the question is


Thus, the measured density is


We have expressed the result with 1 decimal place because the mass was measured to the nearest hundred milligrams (or one-tenth grams). Any further decimal is senseless because that precision comes from calculations, not from measurements.