The answer i got was
n=-3/4,n=-1
If we divide 56 by 4 we get 14. Why by4? So that one number is 3 times the other So he had 14 balls that went into the green bags and 42 (56-14) that went into the red bags. We could just answer the question and say 14 but I think they want to know how many in each green bag.
14 and 42 don't work because they are not the same number of balls. What number is a common factor? 7 is,
We could have 2 green bags and split the 14 balls into 2 groups of 7 and with the remaining 42 - put them into 6 red bags of 7 each.
And so the answer to your question is:
7 ball in each bag = 2 bags are green, and 6 bags are red
14 balls + 42 balls = 56 bouncy balls
Answer:
(0.5, 0.5)
Step-by-step explanation:
Use the midpoint formula: 
The points are:

Therefore, the midpoint between A and C is located at (0.5, 0.5).
Vocab:
Parallel = same slope
Perpendicular = opposite sign and reciprocal slope
-5/2 opposite and reciprocal = 2/5
Solution: they are perpendicular
<span>Because there are 20 coins plus four bars = 24 items to choose. You want to choose where to put the four bars, thus C(24,4). There are four bars, not five. Note that four bars divide the 20 coins into five sections. Five bars would divide it into six, but we only have five different kinds of coins to choose from.</span>