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GenaCL600 [577]
3 years ago
5

Please assist me with these problems using the 45-45-90 relationship triangles​

Mathematics
1 answer:
TiliK225 [7]3 years ago
5 0

Answer:

see below

Step-by-step explanation:

side opposite 90 angle = x \sqrt{2}

sides opposite 45 angle = x

the multiplication and division by  \sqrt{2} should be self explanatory

1. x = 5, y = 5

2. v = 10, u = 10

3. x = \sqrt{10}, y = \sqrt{5}

4. m = 5, n = \frac{5\sqrt{2} }{2}

5. a = \frac{3\sqrt{2} }{2}, b =  \frac{3\sqrt{2} }{2}

6. a = \frac{3\sqrt{2} }{2}, b =  \frac{3\sqrt{2} }{2}

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In which set are all of the numbers solutions to the inequality x < -3?
Tomtit [17]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Eliminate the parameter. x = 1/2t, y = 3t^3 - 1
Elis [28]
X = t/2. t = 2x
y = 3t^3 - 1
y = 3(2x)^3 -1

y = 24x^3 -1
4 0
3 years ago
If f(x) = 2x + 3, what is f(–1)?
Helen [10]

Answer:

Normally, sequences don't go behind 1, but let's see for this one.

f(-1) = 1

Step-by-step explanation:

Let's sub for -1 in x.

f(-1) = 2(-1) + 3.

f(-1) = -2 + 3

f(-1) = 1

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7 0
3 years ago
Read 2 more answers
the height y of a ball thrown by a child is given by y = -1/12x^2 + 2x + 4. how high is the ball when it is at its maximum heigh
zhuklara [117]

Answer:

The height of ball when it is at maximum height is 12  unit

Step-by-step explanation:

Given as :

A ball is thrown by child to height y

And y as a function  x is y = -\frac{1}{12}x^{2}+2x+4

So, for maximum value of height ,

\frac{\partial y}{\partial x}  = 0

Or , \frac{\partial (-\frac{1}{12}x^{2}+2x+4)}{\partial x} = 0

Or, -\frac{1}{12}(2x)+2 = 0

Or, \frac{1}{12}(2x) = 2

or,  x = 12

Hence The height of ball when it is at maximum height is 12  unit  Answer

3 0
3 years ago
Vectors: Find the vector from the point A=(−1,−7,3) to the point B=(3,−2,9).
devlian [24]

Answer:

\overrightarrow {AB} = (4,5,6)

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

Step-by-step explanation:

The vector AB is the vectorial difference between point A and B, that is:

\overrightarrow {AB} = \vec B - \vec A

Given that \vec A = (-1,-7,3) and \vec B = (3,-2,9), the vector AB is:

\overrightarrow {AB} = (3,-2,9)-(-1,-7,3)

\overrightarrow{AB} = (3-(-1),-2-(-7),9-3)

\overrightarrow {AB} = (4,5,6)

The vectorial equation of the line is represented by:

\langle x, y, z\rangle = \vec A + t \cdot \overrightarrow {AB}

Where t is the parametric variable, dimensionless. Given that \vec A = (-1,-7,3) and \overrightarrow {AB} = (4,5,6)

\langle x,y,z \rangle = \langle -1,-7,3 \rangle + t\cdot \langle 4,5,6 \rangle

Finally, the list of questions are now checked:

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

4 0
3 years ago
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