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2 years ago

What is 2 and 1/3+ 3 and 1/3

Mathematics

1 answer:

pychu [463]2 years ago

4 0

The question is asking you to add mixed numbers together. The two mixed numbers you want to add up are 2 1/3 and 3 1/3.

This question is fairly simpler than other mixed number or fraction types of problems because the fractions attached to the whole numbers already come having common denominators.

This means you don't have to do anything extra to the fractions to add them; you can just add the numerators (top numbers) together and keep the denominators the same.

Add the fractions (1/3) together first.

1/3 + 1/3 = 2/3

Now add the whole numbers together.

2 + 3 = 5

Combine the whole number and the fraction together to create the mixed number as your answer. Your answer is 5 and 2/3.

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[2.4–(0.3–3.21)÷2+0.44÷(−2)]÷ 2/5

netineya [11]

Answer:9.0875

Step-by-step explanation:

[2.4–(0.3–3.21)÷2+0.44÷(−2)]÷ 2/5=

[4.8:2-(-2.91):2-0.44:2]:2/5=

=[(4.8+2.91-0.44):2]*5/2=

=[(7.71-0.44):2]*5/2=

=(7.27:2)*5/2=(7.27*5):(2*2)=

=36.35:4=9.0875

6 0

2 years ago

Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g

SpyIntel [72]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see $\bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
g(x)=&\sqrt{0.5x}\\
&\quad \uparrow \\
&\quad B
\end{array}$

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.

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Anastaziya [24]

Https://us-static.z-dn.net/files/d1e/04b1f4bb9da77e9bfea077c2aeee7a27.jpg

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Victoria has $200 of her birthday gift money saved at home, and the amount is modeled by the function h(x) = 200. She reads abou

svlad2 [7]

Solution :

Amount of money Victoria has = $200

The amount modelled by function = h(x) = 200

According to the function,

s(x) = (1.05)x - 1

It means that the total amount of the interest that Victoria will receive s(x) is equal to original amount of $200 which multiplied by the rate of interest (1.05) and then multiplied by the time that Victoria keeps the money in the bank (x) minus 1.

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2 years ago

Estimate the area under the curve f(x) = x2 from x = 1 to x = 5 by using four inscribed (under the curve) rectangles. Answer to

ozzi

Check the picture below.

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