From the sample used to find out what psychology majors would join the club and if it is biased, we can say that;
<u><em>- Yes, the sampling method is biased. </em></u>
<u><em>- The likely direction of the bias is because you only asked 5 people which </em></u>
<u><em>is not a significant percentage of those offering psychology majors and as </em></u>
<u><em>such the 4 out of 5 gotten is likely going to be an over estimation of those </em></u>
<u><em>who are willing to pay to join this club.</em></u>
We are told that;
- You want to start a club.
- This club is for psychology majors.
- You want to find the proportion of those in the psychology majors that will join this club you want to organize.
- Now, out of all the students offering psychology majors, you only asked 5 of them if they will be interested. Since 4 out of the 5 are interested and you want to use that to form a basis of the proportion of those interested , it would lead to <em>sampling bias</em> since the population is not adequately represented.
Therefore, this would lead to sampling bias and thus the sample is biased.
Read more at; brainly.com/question/12637861
Answer:
mira a las base de las figuras y busca cual base matchs con la figuras de la figura prinsipal
Step-by-step explanation:
como el cono va con la del toda la izquierda de la de la mitad
Answer:
c 5%
Step-by-step explanation:
8000 + 410.7 = 8000 e^(r)
e^r = 1.05127125
r lne = ln1.05127125
r = 0.05006316309 × 100
5%
Answer:
Step-by-step explanation:
12.
the formula for the volume of a cone is V=1/3hπr²
549.5 = 1/3(21)(3.14)(x)^2
549.5 = 7(3.14)(x)^2
549.5 = 21.98(x)^2
549.5 = 21.98(x)^2
divide by 21.98 on both sides
25 = (x)^2
sqrt 25 = sqrt x^2
5 = x
13.
the formula for the volume of a sphere is V=4/3πr^3
v=4/3(3.14)9^3
v=4/3(3.14)729
v=(4.186)729
v=3052.08
14.
the formula for the volume of a sphere is V=4/3πr^3
523=4/3(3.14)r^3
523=4/3(3.14)r^3
523=(4.186)r^3
divide by 4.186 on both sides
124.92=r^3
cube root on both sides
4.998=r
round
5=r
<em><u>Please mark brainliest this took me a while</u></em>
