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3 years ago

7

Stephan buys a melon and divides it into 6 servings. he eats 1/3 of the melon over the weekend. how many piecesof melon does ste

phan eat over the weekend?

2 answers:

nexus9112 [7]3 years ago

6 0

Answer:

The answer is : Stephen ate 2 slices over the weekend.

Step-by-step explanation:

As given,

Stephen buys a melon and divides it into 6 servings.

And he eats 1/3 melon over the weekend.

Which means he ate 1/3 of 6, so the value is :

$\frac{1}{3} \times6$ = 2

Hence, Stephen eats 2 slices over the weekend.

umka21 [38]3 years ago

3 0

He eats 2 pieces because 1/3 of 6 would be 2 leaving 4 pieces remaining.

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On an alien planet with no atmosphere, acceleration due to gravity is given by g = 12m/s^2. A cannonball is launched from the or

almond37 [142]

Answer:

a) $\vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j$ , b) $\theta = \frac{\pi}{4}$ , c) $y_{max} = 84.375\,m$ , $t = 3.75\,s$ .

Step-by-step explanation:

a) The function in terms of time and the inital angle measured from the horizontal is:

$\vec r (t) = [(v_{o}\cdot \cos \theta)\cdot t]\cdot i + \left[(v_{o}\cdot \sin \theta)\cdot t -\frac{1}{2}\cdot g \cdot t^{2} \right]\cdot j$

The particular expression for the cannonball is:

$\vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j$

b) The components of the position of the cannonball before hitting the ground is:

$x = (90\cdot \cos \theta)\cdot t$

$0 = 90\cdot \sin \theta - 6\cdot t$

After a quick substitution and some algebraic and trigonometric handling, the following expression is found:

$0 = 90\cdot \sin \theta - 6\cdot \left(\frac{x}{90\cdot \cos \theta} \right)$

$0 = 8100\cdot \sin \theta \cdot \cos \theta - 6\cdot x$

$0 = 4050\cdot \sin 2\theta - 6\cdot x$

$6\cdot x = 4050\cdot \sin 2\theta$

$x = 675\cdot \sin 2\theta$

The angle for a maximum horizontal distance is determined by deriving the function, equalizing the resulting formula to zero and finding the angle:

$\frac{dx}{d\theta} = 1350\cdot \cos 2\theta$

$1350\cdot \cos 2\theta = 0$

$\cos 2\theta = 0$

$2\theta = \frac{\pi}{2}$

$\theta = \frac{\pi}{4}$

Now, it is required to demonstrate that critical point leads to a maximum. The second derivative is:

$\frac{d^{2}x}{d\theta^{2}} = -2700\cdot \sin 2\theta$

$\frac{d^{2}x}{d\theta^{2}} = -2700$

Which demonstrates the existence of the maximum associated with the critical point found before.

c) The equation for the vertical component of position is:

$y = 45\cdot t - 6\cdot t^{2}$

The maximum height can be found by deriving the previous expression, which is equalized to zero and critical values are found afterwards:

$\frac{dy}{dt} = 45 - 12\cdot t$

$45-12\cdot t = 0$

$t = \frac{45}{12}$

$t = 3.75\,s$

Now, the second derivative is used to check if such solution leads to a maximum:

$\frac{d^{2}y}{dt^{2}} = -12$

Which demonstrates the assumption.

The maximum height reached by the cannonball is:

$y_{max} = 45\cdot (3.75\,s)-6\cdot (3.75\,s)^{2}$

$y_{max} = 84.375\,m$

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3 years ago

What is the answer to this equation -14=d/15

expeople1 [14]

Answer:

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Step-by-step explanation:

multiply 15 to both sides

-14*15 =-210

the 15 on the side with d cancels

Now you have d=-210

Hope this helps!

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PIT_PIT [208]

I believe they are: (2,8), (4,6), (1,7), and (3,5) I could be wrong, but I'm almost certain that's it. Hope that helps.

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3 years ago

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6 Which equation has a solution of s = 9.5 ? F -5s = -47.5 G -3 + s = 12.5 H --2s 19 J –1 + s = 10.5

earnstyle [38]

Answer:

F. -5s = -47.5

Step-by-step explanation:

F. -5s = -47.5

s = -47.5 / -5

s = 9.5

This is the correct option

G. -3 + s = 12.5

s = 12.5 + 3

s = 15.5 (Incorrect option)

J. –1 + s = 10.5

s = 10.5 + 1

s = 11.5 (Incorrect option)

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