The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>
What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2

Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
To learn more about the factor visit:
brainly.com/question/25829061
Answer:
-6
Step-by-step explanation:
20+40=60 and therefor 60 is less than 65
Answer:
Well ,lets see∉ if you add theose numbers togetherФ it maybe it he answer is 4=67 *64 ---4 67x54 5xe4t4 6x