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3 years ago

Simplify 2^4×2^3/2^5×2^4 leaving your answer in index form

Mathematics

2 answers:

IrinaK [193]3 years ago

4 0

Answer:

Your correct answer is 64.

Step-by-step explanation:

2^4 × 2^3/2^5 × 2^4 = 64

denis23 [38]3 years ago

3 0

Step-by-step explanation:

$\frac{2^4 * 2^3}{2^5 * 2^4}$
$\frac{2^(4+3)}{2^(5+4)}$
$\frac{2^7}{2^9}$
2^(7-9)
2^(-2)

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dlinn [17]

Answer:

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Step-by-step explanation:

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3 years ago

Write and solve an inequality to find the values of x for which the perimeter of the rectangle is less than 120.

RSB [31]

Answer:

Inequality : 4x+8 < 120

x<28

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Perimeter of a rectangle (P)= 2 length +2 width

Where:

Width = x

Length = x+4

Replacing with the values given

P = 2 (x+4) + 2x

P = 2x+8+2x

P=4x+8

Since the perimeter of the rectangle must be less than 120:

4x+8 < 120

Solving for x

4x<120-8

4x<112

x<112/4

x<28

Feel free to ask for more if needed or if you did not understand something.

4 0

3 years ago

Use the given minimum and maximum data entries, and the number of classes, to find the class width, the lower class limits,

Gennadij [26K]

Using proportions and the information given, it is found that:

The class width is of 14.375.

The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.

The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

Minimum value is 19.
Maximum value is of 134.
There are 8 classes.
The classes are all of equal width, thus the width is of:

$W = \frac{134 - 19}{8} = 14.375$

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.

The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

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3 years ago

Peter is overweight. He is 105 kg. His aim is to lose 500 g per week. If he manages this, how many weeks will it be until he is

charle [14.2K]

Answer:

30 weeks

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the greatest common factor of 20c^2 and 12w

irga5000 [103]

Answer:

60c

Step-by-step explanation:

12x6

10x6

hope i helped bud! ;)

3 0

3 years ago

Simplify 2^4×2^3/2^5×2^4 leaving your answer in index form ​

Simplify 2^4×2^3/2^5×2^4 leaving your answer in index form