The numbers are 105 and 50
<em><u>Solution:</u></em>
Let "x" be the first number
Let "y' be the second number
Twice a number plus twice a second number is 310
Therefore,
twice of x + twice of y = 310
2x + 2y = 310 ---------- eqn 1
The difference between the numbers is 55
x - y = 55 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 2,
x = 55 + y ------ eqn 3
<em><u>Substitute eqn 3 in eqn 1</u></em>
2(55 + y) + 2y = 310
110 + 2y + 2y = 310
4y = 310 - 110
4y = 200
<h3>y = 50</h3>
<em><u>Substitute y = 50 in eqn 3</u></em>
x = 55 + 50
<h3>x = 105</h3>
Thus the numbers are 105 and 50
Answer:
The height of the cylinder is 4x units.
Step-by-step explanation:
volume of a cylinder = nr^2h
n = 22/7
r = radius = x/2
Let illustrate with an example. If the diameter of a cylinder is 6 and the volume is 6^3 = 216. The radius = 6/2 = 3
n3^2 x h = 216
h = 216/9 = 24
so the height is 4 times the diameter
Area of the base = nr^2
1/2^2 x x = 1/4 pi x^2
Answer:
a. Domain : All Real Numbers
b. Range: y≥ -1
c. The x-intercepts are (0,0) and (-4,0)
d. The y-intercept is (0,0).
e. f(2)=3
f(-2)=-1
Step-by-step explanation:
If this has helped you please mark as brainliest
Answer: If this is a trick question then he still has all 3 but if not he has 1
Step-by-step explanation:
