Answer:
11200 for 7 engines for a total of 80 hours
Step-by-step explanation:
You have 8 engines burning 12000 .for 10 hours.
Divide 10 hours into 12000=1200 PER hour.
1200 ÷8 engines = 140 per hour per engine.
140 × # of hours (12)=1680 for 12 hours per engine.
# of engines × 1680 for 12 hour/per engine
5×1680 = 8400 of fuel for 12 hours/5 engine
Then you have 2 that runs 10 hours
2 × 140 per hour per engine =280 × 10 =2800 for 2 engines for 10 hours
8400. + 2800= 11200 of fuel for 6 engines
Answer:
547 & 544
Step-by-step explanation:
when you round 552 to the nearest 10 its 550 and 544 would be 540.
when rounded to the nearest hundred 552 would be 600 & 544 would be 500.
(could be wrong)
Answer: 4^2 + 9
Step-by-step explanation:
Simplify
4x^2 - 2x + 1 + 2x + 8
Collect like terms
4^2 + (-2x+2x) + (1+8)
Simplify
4x^2 + 9
440d=60t it would take jimmy 7.33 hours to get home if he drove at a constant rate of 60 Miles Per Hour
Answer:The claim is correct
Explanation:Assume the given triangle ABCperimeter of triangle ABC = AB + BC + CA ............> I
Now, we have:D is the midpoint of AB, this means that:
AD = DB = (1/2) AB ..........> 1E is the midpoint of AC, this means that:
AE = EC = (1/2) AC ...........> 2DE is the midsegment in triangle ABC, this means that:
DE = (1/2) BC ...........> 3perimeter of triangle ADE = AD + DE + EA
Substitute in this equation with the corresponding lengths in 1,2 and 3:perimeter of triangle ADE = (1/2) AB + (1/2) BC = (1/2) AC
perimeter of triangle ADE = (1/2)(AB+BC+AC) .........> IIFrom I and II, we can prove that:perimeter of triangle ADE = (1/2) perimeter of triangle ABC
Which means that:perimeter of midsegment triangle is half the perimeter of the original triangle.
Hope this helps :)