Answer:
Draw a perpendicular line from point A to line segment BC. Name the intersection of said line at BC “E.” You now have a right angled triangle AED.
Now, you know AD = 6 m. Next, given that the trapezoid is a normal one, you know that the midpoints of AB and DC coincide. Therefore, you can find the length of DE like so, DE = (20–14)/2 = 3 m.
Next, we will use the cosign trigonometric function. We know, cos() = adjacent / hypotenuse. Hence, cosx = 3/6 = 1/2. Looking it up on a trigonometric table we know, cos(60 degrees) = 1/2. Therefore, x = 60 degrees.
Alternatively, you could simply use the Theorem for normal trapezoids that states that the base angles will be 60 degrees. Hope this helps!
Answer:
Look at the pictures
Step-by-step explanation:
Hope this helps
Dave would pay $16.20 and if u mean 8% tax not 8$ then Mel would pay $21.60
Answer:
x^2 + 3x + 5
Step-by-step explanation:
sum of the two given side = 2x^3 + 3x^2 + 3x -2
missing side = 2x^3 + 4x^2 + 6x + 3 - 2x^3 - 3x^2 - 3x + 2 = x^2 + 3x + 5
For the answer to the question above, we'll have to use the formula for velocity which is v =<u> d
</u> t and d = vt
Since the total distance is given, therefore we can get the time and it will look like this.
220t + 250t = 1880
<u>470t</u> = <u>1880
</u>470 470
the problem indicates that the train runs 250kph
Let's substitute:
d = 250(4)
the distance traveled by Lian is 1000km
<u>
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