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4 years ago

Which statement is true about the sum of two rational numbers?

Mathematics

2 answers:

ioda4 years ago

7 0

Answer:

It can always be written as a fraction.

Step-by-step explanation:

zepelin [54]4 years ago

6 0

Answer: It can always be written as a fraction.

Step-by-step explanation:

1. By definition, a rational numbers has the following form: $\frac{a}{b}$ , where $a$ and $b$ are integers and $b\neq0$ .

2. Therefore, when you add two rational numbers, the result it can always be written as a fraction.

3. An example is shown below:

$\frac{3}{5}+\frac{1}{5}=\frac{4}{5}$

The result is a fraction whose numerator and denominator are integers.

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Numbers 100 to 125 are written on separate slips (one number on one slip), kept in a box and mixed well. One slip is chosen from

Elza [17]

Answer:

1/25

Step-by-step explanation:

In 100 to 125, the difference is 25.

so, there is only 1 possibility of there being 108 from 100 to 125 so its 1/25

5 0

3 years ago

Eye Color Each of two parents has the genotype brown>blue, which consists of the pair of alleles that determine eye color, an

dalvyx [7]

Answer:

A) Brown-Brown ,Brown-Blue, Blue-Brown, Blue-Blue B) 1/4 =0,25 C)3/4=0,75

Step-by-step explanation:

Lets mother's "BROWN" is "BROWN-M",

mother's "BLUE" is " BLUE-M"

Lets father's "BROWN" is "BROWN-F" and

father's "BLUE " is "BLUE-F"

The kid can have the genotype as follows (list of possible outcomes) :

1. BROWN-M>BROWN-F ( received BROWN as from mother as from father)

2. BROWN-M>BLUE-F ( Received BROWN from mother and BLUE from father)

3. BLUE-M>BROWN-F ( Received BLUE from mother and Brown from father)

4. BLUE-M>BLUE-F ( Received BLUE as from mother as from father)

b) As we can see in a) only 1 outcome from 4 is BLUE-BLUE. So the probability of BLUE-BLUE genotype is

P(BLUE>BLUE)=1/4=0.25

c) As we know that if the child has at least one brown allele, that color will dominate and the eyes will be brown.

It means that outcomes BROWN-BROWN, BROWN-BLUE and BLUE-BROWN determine brown color of eye. So the number of these outcomes is 3. Total amount of outcomes is 4.

So probability that eyes are brown is P(Brown eyes)=3/4 =0.75

6 0

4 years ago

Before a computer is assembled, its motherboard goes through a special inspection. Assume only 85% of motherboards pass this ins

andreyandreev [35.5K]

Answer:

(a) The probability that at least 13 of the next 15 motherboards pass inspection is 0.6042.

(b) On average, 1.18 motherboards should be inspected until a motherboard that passes inspection is found.

Step-by-step explanation:

Let X = number of motherboards that pass the inspection.

The probability that a motherboards pass the inspection is P (X) = p = 0.85.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is,

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that at least 13 of the next 15 motherboards pass inspection as follows:

P (X ≥ 13) = P (X= 13) + P (X = 14) + P (x = 15)

$={15\choose 13}0.85^{13}(1-0.85)^{15-13}+{15\choose 13}0.85^{14}(1-0.85)^{15-14}\\+{15\choose 13}0.85^{16}(1-0.85)^{15-15}\\=0.2856+0.2312+0.0874\\=0.6042$