Answer:
Find the relative frequency for the event "heads" for each friend:
Friend 1: 0.59 (41/70)
Friend 2: 0.7 (49/70)
Friend 3: 0.37 (26/70)
If the friends combine their results to get 116 heads and 94 tails, what is the relative frequency for the event "heads"?
0.55 (116/210)
Suppose each friend flips a coin 700 times. Is there a value you would expect the relative frequency for the event "heads" to be close to?
For Friend 1, basing it off the 0.59 frequency from earlier, I would expect the heads to be around 413.
Friend 2, 490
Friend 3, 259
Answer:
x = - 2, x = 6
Step-by-step explanation:
Given f(x) = 18 we require to solve
3 | x - 2 | + 6 = 18 ( subtract 6 from both sides )
3 | x - 2 | = 12 ( divide both sides by 3 )
| x - 2 | = 4
The absolute value function always returns a positive value, however, the expression inside can be positive or negative, thus
x - 2 = 4 ( add 2 to both sides )
x = 6
OR
- (x - 2) = 4
- x + 2 = 4 ( subtract 2 from both sides )
- x = 2 ( multiply both sides by - 1 )
x = - 2
As a check substitute these values into the left side of the equation and if equal to the right side then they are the solutions
x = 6 → 3|6 - 2| + 6 = 3|4| + 6 = 3(4) + 6 = 12 + 6 = 18 ← True
x = - 2 → 3|- 2 - 2| + 6 = 3|-4| + 6 = 3(4) + 6 = 12 + 6 = 18 ← True
Hence solutions are x = - 2, x = 6
X = -5 and 3
You solve using the quadratic equation by using the formula below where the coefficients of each term are the letters in alphabetical order.
Answer: B = (1,-9)
Step-by-step explanation:
