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3 years ago

Points a, b, c are collinear. Point b is between A and C. AC=3x+3, ab=-1+2x, and BC=11. solve x.

Mathematics

1 answer:

romanna [79]3 years ago

5 0

X is 7. Hope this helps! Photo above

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yaroslaw [1]

Answer:

( - 6 , - 1 )

Step-by-step explanation:

Let's find the rule of that transformation:

1 + = 4 ⇒ = 3

9 + = 10 ⇒ = 1

Thus, the rule of given transformation is ( x + 3 , y + 1 )

So, the image of the point ( - 9 , - 2 ) is

( - 9 + 3 , - 2 + 1 ) = ( - 6 , - 1 )

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Step-by-step explanation:

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2. is 5/8 greater than, less than or equal to 11/16

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Does 4(x−8)+12=2(2x−9) have one solution, no solution, or infinitely many solutions? <br><br> ??

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Step-by-step explanation:

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3 years ago

Select the correct answer.

maks197457 [2]

Answer:

See Explanation

Step-by-step explanation:

Your question is poorly formatted. However, I'm able to deduce that your question involves at least 2 algebraic fractions that needs to be simplified.

So, I'll make use of the following expression:

$\frac{3n}{n + 3} + \frac{5}{n - 4}$

When you follow the steps I'm about to provide, you'll arrive at the right answer

Required

Determine an equivalent expression

$\frac{3n}{n + 3} + \frac{5}{n - 4}$

Step 1: Take L.C.M of the denominators

$LCM = (n+3)(n-4)$

Step 2: Evaluate the fractions

$\frac{3n}{n + 3} + \frac{5}{n - 4}$ $= \frac{3n(n-4)+5(n+3)}{(n+3)(n-4)}$

Step 3: Open the brackets at the numerator

$\frac{3n}{n + 3} + \frac{5}{n - 4}$ $= \frac{3n^2-12n+5n+15}{(n+3)(n-4)}$

Step 4: Collect and evaluate like terms

$\frac{3n}{n + 3} + \frac{5}{n - 4}$ $= \frac{3n^2-7n+15}{(n+3)(n-4)}$

<em>Follow the above steps, and you'll be able to solve your question.</em>

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3 years ago