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3 years ago

Two consecutive even integers have a sum of 46

Mathematics

2 answers:

nata0808 [166]3 years ago

8 0

The numbrs are 22 and 24.

eduard3 years ago

5 0

<span>Two consecutive even integers have a sum of 46 are</span> 22 and 24

hope it helps

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Whats the extreme value?y=3(x+5)^(2)-4

natta225 [31]

Answer:

-4

Step-by-step explanation:

y = 3(x+5)²-4
y= 3(x²+10x+25)-4
y= 3x²+30x+75-4
y= 3x²+30x+71

Derivate the function

y' = 6x+30

solve the equation y'= 0

y'= 6x+30
6x+30= 0
6x= -30
x = -5

The extrme value of y is reached in -5

y = 3(-5+5)²-4= -4

6 0

2 years ago

The number of students at Maria's school decreased by 98% of last year's number currently there are 1170 students how many stude

Vitek1552 [10]

X=number of students at Marita's high school last year
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.98x=1170
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2 years ago

Why does the sum of -4 and 3 complain more than the sum of -3 and 5

AlexFokin [52]

Because of its negatives

7 0

2 years ago

The difference of twice a number and 3 is 11

Softa [21]

Let's break this down:

The difference: Something's gotta be subtracted
Twice a number: So 2 times a number, or n
and 3: So we gotta subtract 2n and 3
is 11: The final answer is 11
So altogether is:

2n - 3 = 11

7 0

3 years ago

Is X-13=x+1 true or false

Black_prince [1.1K]

Answer: FALSE.

Step-by-step explanation:

Given the following equation provided in the exercise:

$x-13=x+1$

You need to solve for the variable "x".

In order to solve for "x" you can folllow the steps shown below:

1. You must apply the Addition property of equality and add 13 to both sides of the equation. Then:

$x-13+(13)=x+1+(13)\\\\x=x+14$

2. Finally you need to apply the Subtraction property of equality and subtract "x" from both sides of the equation. So you get:

$x-(x)=x+14-(x)\\\\0=14\ (FALSE)$

Therefore, as you can observe, the given equation has no solutions.

3 0

3 years ago