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vredina [299]
3 years ago
10

Initially there are

Mathematics
2 answers:
cupoosta [38]3 years ago
5 0
The answer is 8748

You do 4x3x3x3x3x3x3x3
Multiply 4 by 3 seven times because each bacteria cell splits into 3 every second

dimaraw [331]3 years ago
3 0
I believe that it is 84 if I did the calculations correctly
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Y = 2/3x - 3 as a function
Ksivusya [100]

Answer:

∫(x) = \frac{2}{3}x - 3

6 0
3 years ago
Read 2 more answers
What is the range of the function y= squareroot of x+5?
Mnenie [13.5K]
Y + 5 = 0
y >= -5
Therefore, you would choose the first answer.
5 0
2 years ago
Read 2 more answers
What is the radius of a circle whose equation is x^2+y^2-10x+6y + 18=0
rjkz [21]

Answer:

Explanation:

We must write this equation in the form

(

x

−

a

)

2

+

(

y

−

b

)

2

=

r

2

Where

(

a

,

b

)

are the co ordinates of the center of the circle and the radius is

r

.

So the equation is

x

2

+

y

2

−

10

x

+

6

y

+

18

=

0

Complete the squares so add 25 on both sides of the equation

x

2

+

y

2

−

10

x

+

25

+

6

y

+

18

=

0

+

25

=

(

x

−

5

)

2

+

y

2

+

6

y

+

18

=

0

+

25

Now add 9 on both sides

(

x

−

5

)

2

+

y

2

+

6

y

+

18

+

9

=

0

+

25

+

9

=

(

x

−

5

)

2

+

(

y

+

3

)

2

+

18

=

0

+

25

+

9

This becomes

(

x

−

5

)

2

+

(

y

+

3

)

2

=

16

So we can see that the centre is

(

5

,

−

3

)

and the radius is

√

16

or 4

6 0
3 years ago
A fireman is heading towards a forest fire and needs to know how far away the fire is. The person in the fire tower can determin
hjlf

Answer: 3.82 miles

Step-by-step explanation:

According to the shown figure, we can imagine the scene as a <u>right triangle</u>, where the tower is located at the right angle, and the fireman and the forest fire located at each of the other two vertices.

So, since we are dealing with a right triangle we can use the Pithagorean Theorem, in order to find the distance from the fireman to the fire d, which is also the hypotenuse.

d^{2}= (2.1 miles)^{2} +(3.2 miles)^{2}

d=\sqrt{(2.1 miles)^{2} +(3.2 miles)^{2}}

Finally:

d=3.82 miles

7 0
3 years ago
It wants me to find the degree of FJE and FJH but these confuse me
ELEN [110]
Here, EJI + FJE = 180    [ Linear-Pair Equation ]
FJE + 135 = 180
FJE = 180 - 135
FJE = 45

Now, FJH + FJE = 180  [Linear-Pair Equation ]
FJH + 45 = 180
FJH = 180 - 45
FJH = 135

Hope this helps!
8 0
3 years ago
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