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olga_2 [115]
3 years ago
6

Please help. question in the photo!

Mathematics
1 answer:
Alja [10]3 years ago
7 0

well, if m = 1, let's see, then f(x) = √(mx) = √(1x) = √x

and then g(x) = m√x = 1√x = √x

well, if both equations are equal, then their ranges are also equal.

now, if m = "any positive real number"

f(x) = √(mx)  = √m √x will yield some value over the y-axis

g(x) = m√x will yield some range over the y-axis, however, "m" is a larger value than "√m".

what that means is that so long "m" is a positive real number, the ranges of f(x) and g(x) will be the same over an infinite range on the y-axis, even though g(x) is moving faster than f(x), f(x) is moving slower because √m makes a stretch transformation which is smaller than one "m" does.

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p = 2l+2w
area (a) = l×w, so solve for one (I'll use l):
a = l \times w \\ l =  a \div w \\ p = 2l + 2w = 2(l + w)
since p = 30, and a = 50, substitute the "a÷w" in for l in the perimeter equation:
p = 2(l + w) = 2((a \div w) + w) \\  = 2((a \div w) + ( {w}^{2} \div w)) \\  p= 2((a +  {w}^{2}) \div w
Now plug in p and a values:
p= 2((a +  {w}^{2}) \div w) \\ 30 = 2((50 +  {w}^{2}) \div w)  \\ 30 \div 2 = (50 +  {w}^{2}) \div w \\ 15w = 50 +  {w}^{2}
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l = a÷w = 50÷5 = 10
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suter [353]

\huge\underline{\overline{\mid{\bold{\red{ANSWER}}\mid}}}

Table 3 is showing a proportional relationship between x and y.

Reason:

The value of x in table 3 is its square of value of y,

x y

4^{2} = 16

8^{2} = 64

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4 0
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