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Sonja [21]
3 years ago
8

Gina has $72 in $1 bills, $5 bills, and $20 bills. If she has three times as many $1 bills as she has $5 bills, and only half as

many $20 bills as $5 bills, how many of each type of bill does each have?
Mathematics
1 answer:
Hoochie [10]3 years ago
6 0
Total number of bills Gina has = $72
Let the number of $5 bills =X
Number of $1 bills = 3X
Number of $20 bills = X/2
Then
X+3X+X/2=72
4X+X/2=72
8X/2+X/2=72
9X/2=72
X=72*2/9
X=16
So
The number of $5 bills = 16
The number of $1 bills = 48
The number of $20 bills = 8
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Cerrena [4.2K]

Answer:

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Step-by-step explanation:

1.

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2.

10 \frac{1}{8} / \frac{3}{4} = 13\frac{1}{2} \\13\frac{1}{2} + \frac{1}{2} = 14

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3 years ago
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