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3 years ago

If the radius of a circle is multiplied by 3, which is true?

Mathematics

2 answers:

saw5 [17]3 years ago

8 0

Answer:

The circumference is tripled

Step-by-step explanation:

If the radius started as 2 the area would be 12.57 and the circumference would be 12.57.

Then if multiply the radius by 3 it would be 6 and the area would be 113.1 and the circumference would be 37.7.

12.57x3=37.7

Therefore the circumference triples when the radius is multiplied by 3.

maks197457 [2]3 years ago

5 0

Answer:

I think that both are true...

If it's one, it's the circumference.

Step-by-step explanation:

So say the radius is x.

The area is πx^2

The circumference is 2xπ

If you multiply it by 3:

The area is 3πx^2

The circumference is 6xπ

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Diego's club earns money for charity when members of the club perform community service after school,each student who does commu

Arlecino [84]

Answer:

Step-by-step explanation:

Given that:

Amount earned when a student does comminty service = $5

Number of students in club = 12

Amount earned E, is a function of number of members (n) who does community service.

Hence,

E = n * amount earned per member

Is 24 a possible output?

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4 0

3 years ago

Applying the Segment Addition Postulate

blsea [12.9K]

Answer:

144

Step-by-step explanation:

Find: Length of segment BC

CD+DB=BC

3x+8+4x+10=BC

7x+18=BC

BC also equals 8x (given on the screen shot)

7x+18= 8x

x=18

18 times 8 = 144

Check:

3( 18) + 8 + 4(18) + 10

54+8 + 72+10

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7 0

3 years ago

What is the perimeter of quadrilateral ABCD with verticals at A(-11,-6) b(-3,0) c(1,0) and d (1,-6)

dedylja [7]

Answer:

32 units

Step-by-step explanation:

We have a quadrilateral ABCD and we are given the following coordinates for these vertices:

A (-11,-6)

B (-3,0)

C (1,0)

D (1,-6)

AB = $\sqrt{(0-(-6))^2+(-3-(-11)^2} = \sqrt{36+64} =\sqrt{100}$ = 10 units

BC = $\sqrt{(0-0)^2+(1-(-3)^2} = \sqrt{0+16} =\sqrt{16}$ = 4 units

CD = $\sqrt{(0-(-6))^2+(1-1^2} = \sqrt{36+0} =\sqrt{36}$ = 6 units

AD = $\sqrt{(-6-(-6))^2+(1-(-11)^2} = \sqrt{0+144} =\sqrt{144}$ = 12 units

Perimeter of ABCD = $10+4+6+12$ = 32 units

6 0

3 years ago