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3 years ago

Anna calculated the area of a parallelogram with a base of 7 2/5 in the height of 2M her work is shown

Mathematics

1 answer:

ZanzabumX [31]3 years ago

3 0

Step-by-step explanation:

Anna calculated the area of a parallelogram with a base of 7 2/5 in the height of 2M her work is shown

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In the figure, the horizontal lines are parallel and AB = BC = CD. If LM = 3 Find JM? A. 12 B. 6 C. 3 D. 9

ziro4ka [17]

A.12 because i had same question

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5 0

3 years ago

September 6 is a Read Book Day.Polina read 5 times as many pages as Marcus read.Together,the read 108 pages.How many pages did e

Gemiola [76]

Answer:

The number of pages that Polina read was 90 and the number of pages that Marcus read was 18

Step-by-step explanation:

Let

x -----> number of pages that Polina read

y ----> number of pages that Marcus read

we know that

x+y=108 ----> equation A

x=5y -----> equation B

substitute equation B in equation A and solve for y

$5y+y=108\\6y=108\\y=18$

Find the value of x

$x=5y -----> x=5(18)=90$

therefore

The number of pages that Polina read was 90 and the number of pages that Marcus read was 18

3 0

2 years ago

What is the answer for -5(a-6) + 2a

katen-ka-za [31]

Answer:

27a

Step-by-step explanation:

-5(a-6)+2a

-5a+30+2a

-3a+30

27a

7 0

3 years ago

Read 2 more answers

Which relation is not a function?

sashaice [31]

It would be 3 beacuse w=3

3 0

3 years ago

What is the value of x in the equation (StartFraction one-half EndFractionx + 12) = StartFraction one-half EndFraction(StartFrac

anastassius [24]

Answer:

$x =-24$

Step-by-step explanation:

Given

$(\frac{2}{3})(\frac{1}{2}x + 12) = (\frac{1}{2})(\frac{1}{3}x + 14) - 3$

Required

Solve for x

$(\frac{2}{3})(\frac{1}{2}x + 12) = (\frac{1}{2})(\frac{1}{3}x + 14) - 3$

Open all brackets

$\frac{2}{3}*\frac{1}{2}x + \frac{2}{3}*12 = \frac{1}{2}*\frac{1}{3}x + \frac{1}{2}*14 - 3$

$\frac{2 * 1}{3 *2}x + \frac{2 * 12}{3}= \frac{1 * 1}{2 * 3}x + \frac{1 * 14}{2} - 3$

$\frac{1}{3}x + \frac{24}{3}= \frac{1}{6}x + \frac{14}{2} - 3$

$\frac{1}{3}x +8= \frac{1}{6}x + 7 - 3$

Collect like terms

$\frac{1}{3}x - \frac{1}{6}x =7 - 3 -8$

$\frac{1}{3}x - \frac{1}{6}x =-4$

Solve fraction

$\frac{2-1}{6}x =-4$

$\frac{1}{6}x =-4$

Multiply both sides by 6

$6 * \frac{1}{6}x =-4 * 6$

$x =-4 * 6$

$x =-24$

8 0

2 years ago