During a school lunch, the cafeteria sold two-fifths as many white milks as chocolate milks. If there were 35 milks sold, how ma
1 answer:
Hello!
As we can see, they sell 2/5 as many white milks and chocolate milks. We can write this as the ratio 2:5. As you can see, we are given the total, which is 35. The total of the ratio in simplest form is 7 (2+5). As you can see, we have to multiply by 5 to get that 7 to 35. Therefore we multiply each part of the ratio by 5 to get our final answer. We can have w represent the white milks while c represents the chocolate milks.
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Therefore there were 25 chocolate milks sold (just to verify 10 is 2/5 of 25).
I hope this helps!
As we can see, they sell 2/5 as many white milks and chocolate milks. We can write this as the ratio 2:5. As you can see, we are given the total, which is 35. The total of the ratio in simplest form is 7 (2+5). As you can see, we have to multiply by 5 to get that 7 to 35. Therefore we multiply each part of the ratio by 5 to get our final answer. We can have w represent the white milks while c represents the chocolate milks.
Therefore there were 25 chocolate milks sold (just to verify 10 is 2/5 of 25).
I hope this helps!
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The pH of the weak acid is 3.21
Butyric acid is known as a weak acid, we need the concentration of [H+] formula of weak acid which is given by this equation :
where [H+] is the concentration of ion H+, Ka is the weak acid ionization constant, and Ma is the acid concentration.
Since we know the concentration of H+, the pH can be calculated by using
pH = -log[H+]
From question above, we know that :
Ma = 0.0250M
Ka = 1.5 x 10¯⁵
By using the equation, we can determine the concentration of [H+]
[H+] = √(Ka . Ma)
[H+] = √(1.5 x 10¯⁵ . 0.0250)
[H+] = 6.12 x 10¯⁴ M
Substituting the value of [H+] to get the pH
pH = -log[H+]
pH = -log(6.12 x 10¯⁴)
pH = 3.21
Hence, the pH of the weak acid c3h7cooh is 3.21
Find more on pH at: brainly.com/question/14466719
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