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Anna [14]
3 years ago
5

Find what 2/4 is multipled by to to get 2/4 divided by 12. Then solve the problem. Do not reduce your answer.

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
8 0

Answer:

Step-by-step explanation:

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0.75n+0.55p will be the total cost before tax.  Now, we need to add on tax.  Tax will be 0.0625 times the total amount, so we can represent the cost by saying 

(0.75n+0.55p) + 0.0625(0.75n+0.55p), so the answer is B.
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Solve for X in the following equation: 9 = 10X + 3
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Step-by-step explanation:

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3 years ago
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Through (4,-4) ; perpendicular to 6y=x-12
BARSIC [14]

y = mx + b

m = slope and b = y-intercept


We can arrange 6y = x - 12 in the form of y = mx + b

                  6y = x - 12

                    y = 1/6(x) - 2

Slope of y = 1/6(x) - 2 is 1/6. Taking the negative reciprocal of the slope we get the slope for the perpendicular line.

Negative reciprocal of 1/6 is -6.

The equation for the perpendicular line is

                  y = -6x + b

To find b we can plug in the x and y values of (4,-4) into it since it passes through those coordinates

                -4 = -6(4) + b

                 b = -4 + 6(4)

                 b = -4 + 24

                 b = 20

So the equation for the perpendicular line is y = -6x + 20

3 0
3 years ago
Simplify 6 - (-2) - 3(-5).<br> -11<br> -7<br> 19<br> 23
Sergeeva-Olga [200]
6 - (-2) - 3(-5) = (6 + 2) + 15 = 8 + 15 = 23

Your answer is D. the last one :)
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A researcher is studying a mouse population in a field. For the first year of her study, she notices that the mouse population d
Montano1993 [528]

Answer:

The 500 mice would be the carrying capacity of the field being studied.

Step-by-step explanation:

For the first year of study, the mouse population demonstrates exponential growth.

But by third year, the mouse population has stabilized at approximately 500 mice.

Thus, this 500 mice would be the carrying capacity of the field being studied.

Carrying capacity is defined as the measure to demonstrate the maximum population size that any given environment can sustain for an unspecified time period.

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