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GuDViN [60]
4 years ago
9

Can someone help me with this geometry problem?

Mathematics
1 answer:
Svetradugi [14.3K]4 years ago
5 0
All of the angles would either be 77 degrees or 103 degrees.
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If f(x) = 4x + 5, what is the value of f(3)? *
Alisiya [41]

Answer:17

Step-by-step explanation

f(x) is a fancy way of saying x.

so basically you're typing 3 in for x because that is what is in the x part of f(x). from there, you'd multiply 4x3, which is 12, and then adding 5 to get 17. Hope this helped

4 0
3 years ago
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What is the slope !! HELP ME ASAP
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-7/4

Step-by-step explanation:

Since the graph is moving down the slope has to be negative we need to write the answer in rise over run rise as in the y range and run as in x range

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3 years ago
5×6+9x4 I'm really really stuck
ololo11 [35]
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3 years ago
Area model to represent 126÷9​
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5 0
3 years ago
What is the product of the two matrices? Fill in the missing elements of the resulting matrix.​
olganol [36]

The product of the given two matrices comes out to be \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Here we are given the 2 matrices as follows-

\left[\begin{array}{ccc}7&-2\\-6&2\end{array}\right] \left[\begin{array}{ccc}1&1\\3&3.5\end{array}\right]

To find the product of 2 matrices, the number of columns in the first matrix must be equal to the number of rows in the second matrix.

Here since both of the matrices are 2 × 2, their product is possible.

Now, to find the product, we need to multiply each element in the first row by each element of the 1st column of the second matrix and then find their sum. Similarly, we do this for all rows and columns.

Therefore,

\left[\begin{array}{ccc}(7*1)+(-2*3)&(7*1)+(-2*3.5)\\(-6*1)+(2*3)&(-6*1)+(2*3.5)\end{array}\right]

= \left[\begin{array}{ccc}(7)+(-6)&(7)+(-7)\\(-6)+(6)&(-6)+(7)\end{array}\right]

= \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Thus, the product of the given two matrices comes out to be \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Learn more about matrices here-

brainly.com/question/13595915

#SPJ1

3 0
1 year ago
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