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Lubov Fominskaja [6]
3 years ago
5

Which associations best describe the data in the table?

Mathematics
1 answer:
IgorC [24]3 years ago
3 0
In order to find out the association, you need to plot the data. Given that m is x, and n is y, after plotting, the graph shows a positive linear association. The graph rises from left to right. So the answer is letter D.
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PLZ HELP COME ON I NEED HELP 50 points
Art [367]

Answer:

9. -6x+10

10. -24x +18y

11. 15y - 10z

12. -8x- 28

13. -7x + 14

14. -24x +12

Step-by-step explanation:

3 0
3 years ago
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Please help me I don’t understand …
DENIUS [597]

Answer:

X=90°

Y=58°

Z=32°

Step-by-step explanation:

X=180°-90°=90°

Y=180°-90°-32°=58°

Z=180°-58°-90°=32°

3 0
3 years ago
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The mean incubation time for a type of fertilized egg kept at 100.2100.2â°f is 2323 days. suppose that the incubation times are
zlopas [31]

To solve this problem, what we have to do is to calculate for the z scores of each condition then find the probability using the standard normal probability tables for z.

The formula for z score is:

z = (x – u) / s

where,

x = sample value

u = sample mean = 23 days

s = standard deviation = 1 day

 

A. P when x < 21 days

z = (21 – 23) / 1

z = -2

Using the table,

P = 0.0228

Therefore there is a 2.28% probability that the hatching period is less than 21 days.

 

B. P when 23 ≥ x ≥ 22

<span>z (x=22) = (22 – 23)  / 1 = -1</span>

P (z=-1) = 0.1587

 

z (x=23) = (23 – 23) / 1 = 0

P (z=0) = 0.5

 

P = 0.5 - 0.1587 = 0.3413

Therefore there is a 34.13% probability that the hatching period is between 22 and 23 days.

 

C. P when x > 25

z = (25 – 23) / 1

z = 2

P = 0.9772

This is not yet the answer since this probability refers to the left of z. Therefore the correct probability is:

P true = 1 – 0.9772

P true = 0.0228

<span>Therefore there is a 2.28% probability that the hatching period is more than 25 days.</span>

8 0
3 years ago
Solve the equation and show all work. 4|x + 1/3| = 20 <br> i'm kind of stuck hhh
34kurt

Absolute value is a function that takes some number and outputs the size of that number, regardless of the sign. By definition, |x|=x if x\ge0, and |x|=-x if x.

For example,

  • |2| = 2 because the input 2 is positive, so the input is unchanged;
  • |-3| = -(-3) = 3 because the input -3 is negative, so the sign is switched.

What this means for this problem is that there are two cases to consider:

  • If x+\frac13\ge0, then \left|x+\frac13\right|=x+\frac13, so that

4\left(x+\dfrac13\right)=20\implies x+\dfrac13=5\implies\boxed{x=\dfrac{14}3}

  • On the other hand, if x+\frac13, then \left|x+\frac13\right|=-\left(x+\frac13\right), so

-4\left(x+\dfrac13\right)=20\implies x+\dfrac13=-5\implies\boxed{x=-\dfrac{16}3}

6 0
4 years ago
A toy that was originally $35 is now marked down to $28. What percentage was the toy marked down to
Mkey [24]

Answer: 20% off

Step-by-step explanation:

35.00 times .20 = 7.00

35.00 minus 7.00 = 28.00

4 0
3 years ago
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