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emmainna [20.7K]

3 years ago

12

What is the additive identity of -17?

2 answers:

Daniel [21]3 years ago

7 0

Answer:

Additive identity is a number, which when added to any number, gives the sum as the number itself. It means that additive identity is “0” as adding 0 to any number, gives the sum as the number itself. For any set of numbers, that is, all integers, rational numbers, complex numbers, the additive identity is 0.

aleksklad [387]3 years ago

3 0

Answer:

Step-by-step explanation:

Additive identity is a number, which when added to any number, gives the sum as the number itself. It means that additive identity is “0” as adding 0 to any number, gives the sum as the number itself. For any set of numbers, that is, all integers, rational numbers, complex numbers, the additive identity is 0.

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The is the mean score ? A.25.5 B.26 C.

pentagon [3]

So to find the mean you add up all the numbers (or the exam scores) which will get you 212 then you take the number and divide it by the total numbers in the set (how many numbers did you add up?)

212 divided by 8 is 26.5 which would be C. I hope this helps!

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3 years ago

(a) 34 is 85% of what number? <br>

Tju [1.3M]

Answer:

$40$

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3 years ago

Find a power series representation for the function. (Give your power series representation centered at x = 0.) f(x) = x2/(x4 +

ella [17]

Answer:

Given the function: $f(x) =\frac{x^2}{x^4+16}$

A geometric series is of the form of :

$\sum_{n=0}^{\infty} ar^n$

Now, rewrite the given function in the form of $\frac{a}{1-r}$ so that we can express the representation as a geometric series.

$\frac{x^2}{x^4+16}$

Now, divide numerator and denominator by $x^4$ we get;

$\frac{\frac{1}{x^2}}{1+\frac{16}{x^4}}$ = $\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2}$

Therefore, we now depend on the geometric series which is;

$\frac{1}{1+x} =\sum_{n=0}^{\infty} (-1)^n x^n$

let $x \rightarrow x^2$ then,

$\frac{1}{1+x^2} =\sum_{n=0}^{\infty} (-1)^n x^{2n}$

to get the power series let $x \rightarrow \frac{4}{x^2}$

so,

$\frac{1}{1+(\frac{4}{x^2})^2} =\sum_{n=0}^{\infty} (-1)^n (\frac{4}{x^2})^{2n}$

Multiply both side by $\frac{1}{x^2}$ we get;

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =\frac{1}{x^2} \cdot \sum_{n=0}^{\infty} (-1)^n (\frac{4}{x^2})^{2n}$

or

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =x^{-2} \cdot \sum_{n=0}^{\infty} (-1)^n (16)^n (x^{-2})^{2n}$

or

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =\sum_{n=0}^{\infty} (-1)^n (16)^n x^{-4n} \cdot x^{-2}$

Using $x^n \cdot x^m = x^{n+m}$

we have,

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =\sum_{n=0}^{\infty} (-1)^n (16)^n x^{-4n-2}$

therefore, the power series representation centered at x =0 for the given function is: $\sum_{n=0}^{\infty} (-1)^n (16)^n x^{-4n-2}$

6 0

3 years ago

Drag the item from them item bank to its corresponding match<br><br><br> Will mark brainless

DanielleElmas [232]

Answers, in order:

1. Acute

2. Congruent

3. Supplementary angles

4. Vertical angles

5. Adjacent angles

6. Adjacent supplementary angles

7. Alternate interior angles

8. Alternate exterior angles

9. Consecutive interior angles

10. Corresponding angles

11. Straight angle

7 0

3 years ago

Pick a two-digit number greater than 25. Rewrite your two-digit number as a difference of two numbers. Show how to use the ident

ahrayia [7]

Answer:

Step-by-step explanation:

X = 26 ; y = 27

(x − y)2 = x² − 2xy + y²

(26 - 27)² = 26² - 2(26)(27) + 27²

(-1)² = 676 - 1404 + 729

1 = 1405 - 1404

1 = 1

5 0

3 years ago