For the given function f(t) = (2t + 1) using definition of Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].
As given in the question,
Given function is equal to :
f(t) = 2t + 1
Simplify the given function using definition of Laplace transform we have,
L(f(t))s =
=
=
= 2 L(t) + L(1)
L(1) =
= (-1/s) ( 0 -1 )
= 1/s , ( s > 0)
2L ( t ) =
=
= 2/ s²
Now ,
L(f(t))s = 2 L(t) + L(1)
= 2/ s² + 1/s
Therefore, the solution of the given function using Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].
Learn more about Laplace transform here
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Answer:
c they are equil
Step-by-step explanation:
The fast food restaurant sold 30 burgers with cheese and 21 burgers without cheese.
As a decimal this would be 0.05
Sorry for the late reply
Answer: -6b - 12 + 8
Step-by-step explanation: To simplify/find an equivalent expression to -6(b + 2) + 8, we just need to get rid of the parentheses. This can be done by multplying -6 by everything insde the parentheses.
-6 × b = -6b
-6 × 2 = -12
Now, we add our answers together. Don't forget to add the 8 to the end!
-6b + -12 + 8
-6b - 12 + 8
Hope this was helpful! Let me eknow if you have any further questions. :)