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UkoKoshka [18]
3 years ago
11

Change 1 h 25 min 29 s to s.​

Mathematics
2 answers:
Oliga [24]3 years ago
8 0

Answer:

1h 25m and 29s is 5,129 seconds

larisa86 [58]3 years ago
8 0

1 hour=60 min=3600 sec

25 min=1500 sec

3600+1500+29=5129 sec

5129 seconds

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Find the product of the 3+ V11 and its conjugate.
erik [133]

Answer:

It would be -2.

Step-by-step explanation:

<u>Key skills: Conjugate, Distribution Property, and Addition/Subtraction </u>

3 + \sqrt{11\\} is your expression. The conjugate is an important concept you need to know to solve this.

Given the expression: a + \sqrt{b\\}

It's conjugate would be: a - \sqrt{b}

(Basically if there is an addition sign between the 2 terms, it would become a subtractions symbol and if there is a subtraction symbol it would become an addition symbol)

1) So the conjugate of  3+ \sqrt{11} would be 3 - \sqrt{11}

2) Now we would have to multiply them

  • (3 + \sqrt{11})(3- \sqrt{11}) is your expression.
  • If you use distribution property, you will get to: 3^{2} + 3\sqrt{11} - 3\sqrt{11} + \sqrt{11}^{2}
  • The two middle terms would cancel out (they both add up to 0), so then we have 3^{2} - \sqrt{11}^2
  • This would simplify into 9-11, which is then <u><em>-2</em></u>

Hope you understood, and have a nice day!! :)

6 0
3 years ago
Is the system of equations consistent and independent, consistent and dependent, or inconsistent?
Bess [88]

Answer: It is consistent as the lines are intersecting lines and it has a unique solution

Step-by-step explanation:

Since we have given two systems of equation :

We need to check whether the system of equations is consistent or inconsistent.

As we know the formula for checking the consistency :

In the first equation, we have

similarly,

In the second equation, we have

So, According to the question, we have

Therfore , it is consistent as the lines are intersecting lines and it has a unique solution.

4 0
3 years ago
An alloy consists of nickel, zinc, and copper in the ratio 2:7:9. How many pounds of nickel have to be used to create alloy that
Hunter-Best [27]

We are given ratio nickel to zinc to copper = 2:7:9.

From this ratio we can see that <em>ratio of nickel to zinc is 2:7</em>.

Let us assume number of pounds of nickel have to be used to create alloy that contains 4.9 lb of zinc is x pounds.

So, we can setup a proportion as :

x : 4.9 =  2:7

Or

\frac{x}{4.9}=\frac{2}{7}

On cross multiplication, we get

7x= 4.9× 2

7x = 9.8

Dividing both sides by 7, we get

x = 1.4.

<h3>Therefore, 1.4 pounds of nickel have to be used to create alloy that contains 4.9 lb of zinc.</h3><h3 />
6 0
3 years ago
A batting machine uses an automatic baseball feeder. During baseball
Inessa05 [86]

The feeders in battling machine are represented in proportions and fractions.

  • The equation that represents the problem is: \mathbf{\frac 16x + 15 = \frac 23x}
  • The feeder can hold <em>30 baseballs</em>, when full

The given parameters are:

<em />\mathbf{Initial = \frac 16x}<em> ------ 1/6 full</em>

<em />\mathbf{Additional = 15}<em> --- baseballs added</em>

<em />\mathbf{Final = \frac 23x}<em> ---- 2/3 full</em>

<em />

So, the equation that represents the problem is:

\mathbf{Initial + Additional = Final}

So, we have:

\mathbf{\frac 16x + 15 = \frac 23x}

The number of baseballs it can hold is calculated as follows:

\mathbf{\frac 16x + 15 = \frac 23x}

Multiply through by 6

\mathbf{x + 90 = 4x}

Collect like terms

\mathbf{4x - x = 90 }

\mathbf{3x = 90 }

Divide through by 3

\mathbf{x = 30 }

Hence, the feeder can hold 30 baseballs, when full

Read more about proportions and fractions at:

brainly.com/question/20337104

5 0
2 years ago
A volleyball player sets the ball in the air, and the height of the ball after t seconds is given in feet by h= -16^2+12t+6. A t
pychu [463]

Answer:

Step-by-step explanation:

The given function is

h=-16t^2+12t+6

The graph of this function is a parabola that opens downwards

The line h(t)=8 intersects this parabola, when

t=0.5,t=0.25

The teammate can spike the ball after 0.25 seconds or 0.5 seconds.

The two solutions are reasonable. When the volleyball is accelerating into the air, it passes a height of 8 after 0.25 seconds.

When the ball is dropping after it attains maximum height, it attains another height of 8 after 0.5 seconds again.

8 0
3 years ago
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