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3 years ago

The points (10, 6) and (7, u) fall on a line with a slope of -4/3. what is the value of u?

1 answer:

3 0

Answer:
u = 10

Explanation:
The slope of the lone can be calculated as follows:
slope = (y2-y1) / (x2-x1)

We are given:
slope = -4/3
point (10,6) representing (x1,y1)
point (7,u) representing (x2,y2)

Substitute with the givens in the above equation and solve for u as follows:
slope = (y2-y1) / (x2-x1)
-4/3 = (u-6) / (7-10)
-4/3 = (u-6) / -3
4/3 = (u-6) / 3
3*4 = 3*(u-6)
4 = u-6
u = 4+6
u = 10

Hope this helps :)

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Thanks in advance :)

scoundrel [369]

The answer is -4 because -4^7=-16384

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3 years ago

Possible solution for 4+x+2-2x=5

MrRissso [65]

Answer:

x=1

Step-by-step explanation:

For algebra always start by rewriting it.

4+x+2-2x=5

Then ask yourself is there any like terms we can combine, and here yes there is. 4 and 2 and x and -2x. Now lets combine them and rewrite.

6-x=5

Now lets get x alone and the quickest way is to subtract 6 to the other side

6-x=5

-6 -6

-x=-1

Now the two negatives cancel out as you would divide both sides by the coefficient -1 to get positive x alone. We can make this easier by just canceling out the negatives.

Your answer is

x=1

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3 years ago

What is the GCF of 54 and 32?

Musya8 [376]

3
32: 2 2 2 2 2
GCF: 2

8 0

3 years ago

Read 2 more answers

How many square centimetres are in 0.0075 square metres

lidiya [134]

Answer:

75 square centimeters

Step-by-step explanation:

Multiply by 10,000

Can you make me brainliest it would help a lot!

4 0

3 years ago

Read 2 more answers

Archaeologists can determine the diets of ancient civilizations by measuring the ratio of carbon-13 to carbon-12 in bones found

Vsevolod [243]

Answer:

Step-by-step explanation:

The null and the alternative hypothesis are:

H₀=μ₀=μ₁=μ₂=μ₃=μ₄

H₁=two or more μ are different X

Let $X_{ij}$ denote the jth observation of the ith sample. The mean and the variance of the ith sample is given by

$Xbar_{i}$ = $\frac{1}{J_{i}} summation(X_{ij})$ where J=1 to $J_{i}$ and $J_{i}$ is ith sample size

$s_{i} ^{2} =\frac{1}{J_{i}-1 }summation (X_{ij} - Xbar_{i})^{2}$

The sample sizes are J₁ =12 J₂=10 J₃=18 J₄=9

the total number in all samples combined is 49

finding Xbar₁ and s₁

Xbar₁= 1÷12(17.2+....+13.4)

Xbar₁= 17.0500

s₁²= 1÷(12-1) [(17.0500-17.2)+...+(17.0500-13.4)]

s₁²=5.1336

Similarly find the means and variances of other samples

$\left[\begin{array}{ccc}i&Mean&variance\\1&17.0500&5.1336\\2&15.4500&13.2317\\3&16.4972&6.9460\\4&15.4444&7.4428\end{array}\right]$

the sample grand mean denoted by Xbar is the average of all sampled items taken together:

Xbar= $\frac{1}{49}$ (17.2+.....+16.7)

Xbar=16.2255

Compute the treatment sum of squares SSTr, the sum of squares SSE and the total sum of squares SST

SSTr = ∑ $J_{i} (Xbar_{i} -Xbar)^{2}$ from i=1 to 49

SSTr= 20.9910

$SSE= \sum\limits^I_{i=1}\sum\limits^{J_i}_{j=1}(Xbar_{ij}-Xbar_i)^{2}$

$SSE=\sum\limits^I_{i=1}(J_i-1)s_i^{2}$

SSE=(12-1)(5.1336)+...(9-1)(7.4428)

SSE=353.1796

SST=SSTr+SSE

SST=374.1706

Find the treatment mean square MSTr and the error mean square MSE:

MSTr= SSTr/(I-1)

MSTr=6.9970

MSE=SSE/(N-I)

MSE=7.8484

$F=\frac{MSTr}{MSE}$

F=0.89

The degrees of freedom are I-1=3 for the numerator and N-I=45 for the denominator. Under H₀, F has an $F_{3,45}$ distribution. To find the P value we consult the F table.

P>0.100

The complete ANOVA table is below

$\left[\begin{array}{cccccc}source&DF&SS&MS&F&P\\Agegroup&3&20.9910&6.9970&0.89&0.453\\Error&45&353.1796&7.8484\\Total&48&374.1706\end{array}\right]$

(b) The P-value is large. A follower of 5% rule would not reject H₀. Therefore, we cannot conclude the concentration ratios differ among the age groups

4 0

3 years ago