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MA_775_DIABLO [31]
3 years ago
11

Given l||m and m∠1 = 60°, select all angles that are also equal to 60°.

Mathematics
2 answers:
stiv31 [10]3 years ago
6 0

Answer:

m<3

m<2

m<4

Step-by-step explanation:

serg [7]3 years ago
4 0

Answer:

m∠2

m∠3

m∠4

Step-by-step explanation:

we know that

m∠2=m∠1 ----> by vertical angles

m∠3=m∠1 ---- by corresponding angles

m∠4=m∠1 ----> by alternate exterior angles

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PLZZZZ HURRY ILL GIVE BRAINLEST POINTS PLZZZZ I NEED A 100% ON THIS TEST
yuradex [85]

Answer:

y=2/3-1

Step-by-step explanation:

Two coordinate points are (-3,-3) and (3,1). If you use Y2-Y1/X2-X1, you will find the slope. Then use y=mx+b to find the equation.

More detailed:

1+3/3+3 ** It is + because when there are minus signs it turns to a plus

4/6 Then simplify it

2/3

Now that the slope is found, we need to use y=mx+b

(I used the point (3,1))  1=2/3(3)+b

                                    1=2+b

                                    -1=b

I hope this is helpful gl on the test! :)

7 0
3 years ago
I need help with this problem <br><br> Someone explain this to me
Anton [14]

Answer:

16.5

Step-by-step explanation:

Look at the relation between the 2 sides that you have measurements for. One is 16cm, the other 24cm. This means that triangle 2 is 1.5 times larger than triangle 1. Multiply the known measurement from tringle 1, 11cm by 1.5 and you get 16.5 cm

5 0
3 years ago
What bigger 5qt or 10 pt
telo118 [61]
1\ qt=2\ pt\\\\therefore\\\\5\ qt=5\times2\ pt=10\ pt\\\\Answer:\boxed{5\ qt=10\ pt}
8 0
3 years ago
Simplify: <img src="https://tex.z-dn.net/?f=4%5Csqrt%7B320%7D%20-%203%5Csqrt%7B80%7D" id="TexFormula1" title="4\sqrt{320} - 3\sq
aleksandrvk [35]

Answer:

20 √ 5

Step-by-step explanation:

1. You'll need to simplify each term. You'll get 32 √ 5-12 √ 5.

2. After you subtract  12 √ 5  from 32 √ 5, you'll get 20 √ 5.

8 0
4 years ago
Which figure has the same area as the parallelogram shown below? A. A triangle with a base of 4 mm and a height of 20 mm B. A tr
Arisa [49]
<h2>Answer:  A trapezoid with bases of 6 mm and 14 mm and a height of 8 mm </h2>

The parallelogram in the figure has an area of 80mm^{2}, according to the following formula, which works for all rectangles and parallelograms:

A_{parallelogram}=(b)(h)   (1)

Where b is the base and h is the height

The<u> area of a triangle</u> is given by the following formula:

A_{triangle}=\frac{1}{2}(b)(h)   (2)

So, for option A:

A_{triangle}=\frac{1}{2}(4mm)(20mm)=40mm^{2} \neq 80mm^{2}    

Now, the <u>area of a trapezoid </u>is:

A_{trapezoid}=\frac{1}{2}(b_{1}+ b_{2})(h)   (3)

For option B:

A_{trapezoid}=\frac{1}{2}(15mm+25mm)(2 mm)=40mm^{2} \neq 80mm^{2}    

For option C:

A_{trapezoid}=\frac{1}{2}(6mm+14mm)(8 mm)=80mm^{2}>>>>This is the correct option!

For option D:

A_{rectangle}=(30mm)(8mm)=240mm^{2} \neq 80mm^{2}    

<h2>Therefore the correct option is C</h2>
5 0
3 years ago
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