Question

Joe is the oldest of three brothers whose ages are consecutive even integers. Three times age of the Middle brother is 12 less than twice the sum of the ages of joe and the youngest brother. Find Joe's age.

Answer 1

Answer:

The age of Age of Joe is 14 years .

Step-by-step explanation:

Given as :

The statement is

Three times age of the Middle brother is 12 less than twice the sum of the ages of Joe and the youngest brother .

As The age of brothers are consecutive even integers

Let The Age of oldest brother Joe = 2 x + 4

Let The Age of middle brother  = 2 x + 2

Let The Age of younger brother  = 2 x

Now, According to statement

3 × (2 x + 2) = 2 × [ (2 x + 4) + (2 x) ] - 12

Or, 3 × 2 x + 3 × 2 = 2 × (2 x + 4) + 2 × (2 x) - 12

Or, 6 x + 6 = 2 × 2 x + 2 × 4 + 4 x - 12

Or, 6 x + 6 = 4 x + 8 + 4 x - 12

Or, 6 x + 6 = 8 x - 4

Or, 8 x - 6 x = 6 + 4

Or, 2 x = 10

∴    x = $\dfrac{10}{2}$

i.e  x = 5

So, The age of Age of oldest brother Joe = 2 x + 4 = 2 × 5 + 4 = 14 years

The Age of middle brother = 2 x + 2 = 2 × 5 + 2 = 12 years

The Age of younger brother  = 2 x = 2 × 5 = 10 years

Hence, The age of Age of Joe is 14 years . Answer