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3 years ago

PLEASE HELP ME ASAP WILL MARK BARINLIEST

Mathematics

1 answer:

Lesechka [4]3 years ago

8 0

Answer:

Yes, she is Correct

Step-by-step explanation:

I could prove this through writing the exponential equation that resembles this equation, but it's simpler than that:

It mentions that the population would be half of what it was before (a decade before). Now it is safe to say that every exponential (not decaying) equation gradually increases so that every value differs from it's consecutive value through multiplication of a constant.

That is why, given the population would be half of what it was before, 0.5 acts as the 'constant' and the word problem can be modeled by an exponential graph + exponential function.

You might be interested in

Evaluate -8 x |2|. A.-16 B.-10 C.16 D.10

Elis [28]

Step-by-step explanation:

|| represents the absolute value function:

|x| = x when x >= 0,

|x| = -x when x < 0.

Therefore (-8) * |2| = (-8) * 2 = -16. (A)

5 0

3 years ago

Read 2 more answers

Let f(x)= x^2-4x-c. Find a nonzero value of c such that f(c)=c.

Dimas [21]

Answer:

The nonzero value of c will be:

$c = 6$

Step-by-step explanation:

Given the function

$f\left(x\right)=\:x^2-4x-c$

$f\left(c\right)=\:c^2-4c-c$

$f(c) = c$

$c=\:c^2-4c-c$

switching the sides

$c^2-4c-c=c$

subtract c from both sides

$c^2-4c-c-c=c-c$

$c^2-6c=0$

$c\left(c-6\right)=0$

Using the zero factor principle

$\:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$c=0\quad \mathrm{or}\quad \:c-6=0$

so, the solutions to the quadratic equations are:

$c=0,\:c=6$

Therefore, a nonzero value of c will be:

$c = 6$

5 0

3 years ago

F(x)= x^2-8x+15

mash [69]

If I'm reading your equations correctly, they are:f(x)=x2-8x+15g(x)=x-3h(x)=f(x)/g(x)The domain of a function is the set of all possible inputs, what we can plug in for our variable.The largest two limitations on domains (other than explicit limitations, like in piecewise functions) are radicals and rational functions. With radical expressions we know that we CANNOT take an even root of a negative number. I don't see that problem here. With rationals we know that we CANNOT divide by zero. So the question becomes, when does h(x) ask us to divide by zero? When is the denominator of h(x) zero?Since the denominator of h(x) is g(x), we cannot let g(x) equal zero. So when does that happen? when x-3=0 or when x=3. I hope you see here that if x=3, then g(x)=0, and so h(x)=f(x)/0, which we CANNOT do. The domain of h(x) is all real numbers not equal to 3. There is more going on here. If you had factored f(x) first, you could have written h(x) in a confusing way:h(x)=( f(x) ) / ( g(x) )h(x)= ( (x-5)(x-3) ) / (x-3) Right here, it looks like (x-3) will cancel out from the top and bottom of your fraction. It does, in a way. The graph of h(x) will behave exactly like the line y=x-5, except that it has a hole in it at x=3 (check this! it's cool!)SOOO, the takeaway is that it is better to determine limitations on your domain BEFORE over-simplifying your equations.

6 0

3 years ago

The set M represents multiples of 4 from 6 to 38. M=8,12,16,20,24,28,32,36 The set N represents even numbers from 4 to 13. N=4,6

Tomtit [17]

Answer:

The correct option is B. 2

So there are two elements that is 8, 12 in the set M⋂N .

Step-by-step explanation:

Given:

M is a set of multiples of 4 from 6 to 38

i.e M = { 8, 12, 16, 20, 24, 28, 32,36 }

N is a set of even numbers from 4 to 13

i.e N = { 4, 6, 8, 10, 12 }

To Find:

M⋂N = ?

Solution:

Set:

A set is a well-defined collection of distinct objects, considered as an object in its own right.

Examples :

M is a set of multiples of 4 from 6 to 38

i.e M = { 8, 12, 16, 20, 24, 28, 32,36 }

N is a set of even numbers from 4 to 13

i.e N = { 4, 6, 8, 10, 12 }

M⋂N = set of those numbers which are present in M as well as in N

∴ M⋂N = { 8, 12 }

So there are two elements that is 8, 12 in the set M⋂N .

8 0

3 years ago

Claudia was cooking breakfast for her entire family she may double the amount of chocolate chip pancakes as she did regular panc

maw [93]

Answer: she made 36 chocolate chip pancakes, 18 regular pancakes, 9 blueberry pancakes and 27 sausagesl

Step-by-step explanation:

Let w represent the number of chocolate chip pancakes that she made.

Let x represent the number of regular pancakes that she made.

Let y represent the number of blueberry pancakes that she made.

Let z represent the number of sausages that she made.

she made double the amount of chocolate chip pancakes as she did regular pancakes. This means that

w = 2x

x = w/2

she only made half as many blueberry pancakes and she did regular pancakes. This means that

y = x/2

y = w/4

she made triple the amount of sausage as blueberry pancakes. This means that

z = 3y

z = 3w/4

if she cooked 90 items total, it means that

w + x + y + z = 90 - - - - - - - - - -1

Substituting x = w/2, y = w/4 and z = 3w/4 into equation 1, it becomes

w + w/2 + w/4 + 3w/4 = 90

Multiplying through by 4, it becomes

4w + 2w + w + 3w = 360

10w = 360

w = 360/10

w = 36

x = w/2 = 36/2

x = 18

y = w/4 = 36/4

y = 9

z = 3y = 3 × 9

z = 27

6 0

4 years ago