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serious [3.7K]
3 years ago
14

Consider the function g(x) below. What are the values of the function when x=0 and x=6.

Mathematics
1 answer:
Sliva [168]3 years ago
3 0

Answer:

Consider the function below. g(x) = 250 + 8x^3 + x^4 (a) Find the interval of increase. (Enter your answer in interval notation.) Find the interval of decrease. (Enter your answer in interval notation.) (b) Find the local minimum value(s). (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) Find the local maximum value…

Step-by-step explanation:

You have to study

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$4.95 chocolate bars are now on sale for 35% off. what will the chocolate bars cost now? (show work)
Tema [17]
= 4.95 X .65 = 3.2175 ( 3.22).
4.95 = 100% of the price
100 less 35 = 65
4.95 X .65% = 3.2175 or 3.22
6 0
3 years ago
Can someone please help me with this geometry please?
Crank

Answer:

<u>5x+13</u> ÷ 36 = 6x-2 ÷ 30

5x+13 ÷ 6 = 6x-2 ÷ 5

25x+65=36x-12

11x=77 → x=7

<u />

Step-by-step explanation:

5 0
2 years ago
A horticulturist working for a large plant nursery is conducting experiments on the growth rate of a new shrub. Based on previou
valkas [14]

Answer:

t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771    

The degrees of freedom are given by:

df=n-1=48-1=47  

And the p value would be:

p_v =P(t_{(47)}    

Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

Step-by-step explanation:

Information given

\bar X=1.8 represent the sample mean for the growth

s=0.5 represent the sample standard deviation    

n=48 sample size    

\mu_o =2 represent the value that we want to compare

\alpha=0.01 represent the significance level

t would represent the statistic    

p_v represent the p value

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 2cm per week, the system of hypothesis are :    

Null hypothesis:\mu \geq 2    

Alternative hypothesis:\mu < 2    

Since we don't know the population deviation the statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

Replacing the info given we got:

t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771    

The degrees of freedom are given by:

df=n-1=48-1=47  

And the p value would be:

p_v =P(t_{(47)}    

Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

6 0
3 years ago
Angle 1 and angle 2 are supplementary angles. If the measure of angle 1 is 64°. What is the measure of angle 2?
Fed [463]

Answer:

116

Step-by-step explanation:

supplementary means 180 so 180-64 = 116

hope this helps! :)

6 0
2 years ago
Read 2 more answers
Brainliest if correct
dexar [7]

Answer:

w = 9

Step-by-step explanation:

18 + 4w = 6w

6w - 4w = 2w

2w = 18

18/2 = 9

2w/2 = w

w = 9

5 0
2 years ago
Read 2 more answers
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