Given 6(x) = (x+41, what is b(-10)?

Mathematics

1 answer:

prisoha [69]2 years ago

7 0

The value of $b(-10)$ is 31

Explanation:

The given expression is $b(x)=x+41$

We need to determine the value of $b(-10)$

The value of $b(-10)$ can be determined by substituting $x=-10$ in the expression $b(x)=x+41$

Thus, we have,

$b(-10)=-10+41$

Adding the terms, we have,

$b(-10)=31$

Thus, the value is 31.

Therefore, the simplified value of the expression by substituting $x=-10$ in the expression $b(x)=x+41$ is 31.

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