Change it into the form
ax^2 + bx + c = 0
x^2 + 13x + 0 = 0
This equation has a common factor, x. Factorise it out.
<h2>x (x + 13) = 0</h2>
Answer: x < 2
Explanation: To solve for <em>x</em> in this inequality, our goal is the same as it would be if this were an equation, to get <em>x</em> by itself on one side.
Since 3 is being subtracted from <em>x</em>, we add 3
to both sides of the inequality to get <em>x < 2</em>.
Before we graph, write your answer in set notation.
We can write this as {x: x < 2}.
It's important to understand what this means.
This means that any number less than 2 is a solution to this inequality.
I have graphed the inequality for you below.
Start with an open dot on +2.
We use an open dot because +2 is not included as a solution.
Then draw an arrow going to the left.
Observe the given data distribution table carefully.
The 5th class interval is given as,

The upper limit (UL) and lower limit (LL) of this interval are,

Thus, the upper-class limit of this 5th class is 17.4.