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blsea [12.9K]
3 years ago
10

A circle is defined by the equation x2 + y2 + 8x + 22y + 37 = 0. What are the coordinates for the center of the circle and the l

ength of the radius?
Mathematics
1 answer:
inn [45]3 years ago
6 0
We can say that:
8x = -2ax
8 = -2a
a = -4

22y = - 2by
22 = -2b
b = -11

37 = a² + b² - r²
37 = (-4)² + (-11)² - r²
r² = 16 + 121 - 37
r² = 100
r = 10

With all this information, we can say that:
The center of the circle is: (-4 ; -11)
and the radius of the circle is r = 10

P.S:
(a - x)² + (b-y)² = r²
a² - 2ax + x² + b² -2by + y² - r² = 0
x² + y² -2ax - 2by + a² + b² - r² = 0

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Which expressions are polynomials?
igor_vitrenko [27]

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Option B: 6 + w

Option D: 2 x^{4}-y

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Let us first define the polynomial.

A polynomial can have constants, variables, exponents and fractional coefficients.

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Option A: z + 1

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Option B: 6 + w

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Change y-7=m(x-4) to standard form
Ivan

Answer:

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Step-by-step explanation:

Standard form is ...

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where a, b, c are mutually prime integers and a > 0.

If we assume m > 0, then we need to collect the variable terms on the right side of the equation, so the coefficient of x will be positive.

  y -7 = mx -4m . . . . eliminate parentheses

  -7 = mx -y -4m . . . . subtract y

  4m -7 = mx -y . . . . . add 4m

  mx -y = 4m -7 . . . . . . standard form

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2 years ago
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