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blsea [12.9K]
3 years ago
10

A circle is defined by the equation x2 + y2 + 8x + 22y + 37 = 0. What are the coordinates for the center of the circle and the l

ength of the radius?
Mathematics
1 answer:
inn [45]3 years ago
6 0
We can say that:
8x = -2ax
8 = -2a
a = -4

22y = - 2by
22 = -2b
b = -11

37 = a² + b² - r²
37 = (-4)² + (-11)² - r²
r² = 16 + 121 - 37
r² = 100
r = 10

With all this information, we can say that:
The center of the circle is: (-4 ; -11)
and the radius of the circle is r = 10

P.S:
(a - x)² + (b-y)² = r²
a² - 2ax + x² + b² -2by + y² - r² = 0
x² + y² -2ax - 2by + a² + b² - r² = 0

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Basile [38]

Answer: y = -3x - 6

Step-by-step explanation:

One way to write a <u>linear equation</u> is with slope-intercept form.               Slope-intercept form is y = mx + b, where m is the slope, and b is the              y-intercept.

Thus, the equation is y = -3x - 6

Hope it helps :) and let me know if you are confused anywhere.

8 0
2 years ago
Read 2 more answers
Two separate tests are designed to measure a student's ability to solve problems. Several students are randomly selected to take
Ipatiy [6.2K]

Answer:

a) r = 0.974

b) Critical value = 0.602

Step-by-step explanation:

Given - Two separate tests are designed to measure a student's ability to solve problems. Several students are randomly selected to take both test and the results are give below

Test A | 64 48 51 59 60 43 41 42 35 50 45

Test B |  91 68 80 92 91 67 65 67 56 78 71

To find - (a) What is the value of the linear coefficient r ?

             (b) Assuming a 0.05 level of significance, what is the critical value ?

Proof -

A)

r = 0.974

B)

Critical Values for the Correlation Coefficient

n       alpha = .05          alpha = .01

4           0.95                       0.99

5           0.878                     0.959

6           0.811                       0.917

7           0.754                      0.875

8           0.707                      0.834

9           0.666                      0.798

10          0.632                      0.765

11           0.602                      0.735

12          0.576                       0.708

13          0.553                       0.684

14           0.532                       0.661

So,

Critical r = 0.602 for n = 11 and alpha = 0.05

6 0
3 years ago
Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. C = 71°, a = 27, c = 26
guajiro [1.7K]

We have

SinC/ c  = Sin A / a

Sin 71/ 26 = Sin A / 27

Sin A  = 27 Sin 71 /  26  = about .982

So°

Sin-1(.982)  = A  = 79. 08°

Then angle B = 180 - 71 - 79.08 = 29.92°

And b is given by

b/sin29.92  = 26/sin 71

b = 26sin29.92/sin71 =  about 13.72

But A could also be an obtuse angle = 180 - 79.08 =  100.92°

So we have

B = 180 - 71 - 100.92 = 8.08°

And we have

b / sin 8.08  = 26/sin71

b = 26sin8.08/sin 71 = 3.865

8 0
3 years ago
Answer this and I’ll make you Brainly
FrozenT [24]
The answer is f(x) = (x/4) - 3

4/4=1-3=-2
8 0
3 years ago
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Simplify. 8u+9v+3u−5v
musickatia [10]
Combine like terms
8u+3u= 11u
and
9v-5v= 4v
So the answer is 11u+4v
8 0
3 years ago
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