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3 years ago

What is bigger 0.75 or 1 3/4

Mathematics

1 answer:

Simora [160]3 years ago

5 0

1 3/4 is greater than 0.75 because 1 3/4 is 1.75 and it is greater than 0.75

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What is 0.366 in expanded notation

oksano4ka [1.4K]

3 × 1/10 + 6 × 1/100 + 6 × 1/1000
I'm pretty sure that's it but I'm not good at math

4 0

3 years ago

party trays, which cost $14.00 to make not including labor, are sold for $35.00. if two people work 8 hour shifts making the tra

olasank [31]

Answer:

I think its $76

Step-by-step explanation:

please help brainly.com/question/20406553

7 0

2 years ago

Help me please algebra 2 PLEASSEEEEE!!!

liq [111]

Answer:

29.74 degrees.

Step-by-step explanation:

Tan(theta) = opposite / adjcent.

opposite = 8

adjacent = 14

Tan(theta) = 8/14

Tan(theta) = 0.5714

theta = tan^-1(0.5714)

theta = 29.74 degrees

5 0

3 years ago

Recall that two angles are complementary if the sum of their measures is 90 degreesÂ°. Find the measures of two complementary an

raketka [301]

Answer:

18° and 72°

Step-by-step explanation:

let x be the measure of one angle then the other is 3x + 18

The sum of the 2 complementary angles = 90°, hence

x + 3x + 18 = 90

4x + 18 = 90 ( subtract 18 from both sides )

4x = 72 ( divide both sides by 4 )

x = 18

the 2 angles are 18° and (3 × 18 ) + 18 = 72°

8 0

3 years ago

A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a

sineoko [7]

ANSWER

The scale factor is
$2.5$

EXPLANATION

The given triangle has vertices,

$A(0,0),B(0,4),\:and\:C(6, 0)$ .

The vertices of the image triangle is,

$A'(0,0),B'(0,10),\:and\:C'(15, 0)$ .

The scale factor is given by

$k = \frac{image \: length}{object \: length}$

So we can use any of the corresponding sides to determine the scale factor,

$k = \frac{|A'B'|}{ |AB|}$

$k = \frac{ |10 - 0| }{ |4 - 0|}$

$k = \frac{ |10| }{ |4 |} = \frac{10}{4} = 2.5$

Or

$k = \frac{|A'C'|}{ |AC|}$

$k = \frac{ |15 - 0| }{ |6 - 0|}$

$k = \frac{ |15| }{ |6|} = \frac{15}{6} = 2.5$

Or

$k=\frac{|B'C'|}{|BC|}$

$k = \frac{\sqrt{(15 - 0)^2+(0-10)^2 }}{\sqrt{(6 - 0)^2+(0-4)^2}}$

$k = \frac{ 5\sqrt{13}}{2\sqrt{13}} = \frac{5}{2} = 2.5$

The correct answer is C

3 0

2 years ago