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Anit [1.1K]
3 years ago
15

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics
1 answer:
Kruka [31]3 years ago
3 0

x^3+8y^6=x^3+2^3(y^2)^3=x^3+(2y^2)^3\\\\\text{use}\ a^3+b^3=(a+b)(a^2-ab+b^2)\\\\x^3+(2y^2)^3=(x+2y^2)(x^2-(x)(2y^2)+(2y^2)^2)=(x+2y^2)(x^2-2xy^2+4y^4)

Answer:\ (x+2y^2)(x^2-2xy^2+4y^4)

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Enny White is shopping for CDs. She decides to purchase 3 movie soundtracks. The music store has 7 different movie soundtracks i
zubka84 [21]

Answer:

35\ ways

Step-by-step explanation:

we know that

<u><em>Combinations</em></u> are a way to calculate the total outcomes of an event where order of the outcomes does not matter.

To calculate combinations, we will use the formula

C(n,r)=\frac{n!}{r!(n-r)!}

where

n represents the total number of items

r represents the number of items being chosen at a time.

In this problem

n=7\\r=3

substitute

C(7,3)=\frac{7!}{3!(7-3)!}\\\\C(7,3)=\frac{7!}{3!(4)!}

simplify

C(7,3)=\frac{(7)(6)(5)4!}{3!(4)!}

C(7,3)=\frac{(7)(6)(5)}{3!}

C(7,3)=\frac{(7)(6)(5)}{(3)(2)(1)}

C(7,3)=35\ ways

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3 years ago
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3 years ago
Solve For H ---I&gt; A=1/2(B₁+B₂)h
Alex

Answer:

  • h = 2A/(B₁+B₂)

Step-by-step explanation:

<u>Given equation</u>

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B = amount of students who chose Bulldog

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so.. "t" chose tiger, ok

"<span>Four times as many students chose Bulldog as chose Tiger"
namely, if "t" chose tiger, then 4 times that many chose Bulldog, thus

b = 4t

"</span><span>Twice as many students chose Lion as chose Tiger"
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n = 2t

now, we know a total of 273 students were surveyed, thus

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Read 2 more answers
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