G(x)= x^2-6x-7
g(2)= 2^2 - 6×2 - 7 = -15
f(x)= x + 8
f(g(2))= -15 + 8 = -7 thus a is answer
Answer:
m∠SPQ = (9x + 7)°
Step-by-step explanation:
In the given rhombus PQRS,
m∠SPQ = m∠SPR + m∠QPR
By substituting the given values,
m∠SPQ = (4x + 11)° + (5x - 4)°
= (4x + 5x) + (11 - 4)
= 9x + 7
Therefore, m∠SPQ = (9x + 7)° will be the answer.
The missing steps are each right angles and .
Solution:
Step 1: Given data:
Step 2: In the two polygons,
and
(Each right angle)
Step 3: Given
Step 4: By third angle theorem,
If two angles in one triangle are congruent to the two angles in the other triangle, then the third angles in the triangles also congruent.
Step 5: By the definition of congruent polygons,
If two same shape polygons have all the angles are congruent and all the corresponding sides are congruent then the polygons are congruent.
Hence .
Therefore the missing steps are each right angles and .
1km/h
half hours= 30 min
avarage speed= total distance ÷total time
remember it.
Answer:
Y= 1/4x +2
Step-by-step explanation:
The y intercept is +2 (positive 2 on the Y ☝ line) and the slope is counting on the X axis first, then counting ☝ on the y... Until you get to the next point that is not on the white part of the graph. For example: Counting from (0, 2) to (1, 6) would be rise over run aka 1()/4(☝). Sorry if that was needlessly complicated... Basically solid point, rise/run, next solid point = slope. Solid point on y line = y intercept.