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Alchen [17]
4 years ago
6

In the figure below, find the m

Mathematics
1 answer:
Zina [86]4 years ago
4 0

8x+ 18 + 3x-3 = 180  straight line

combine like terms

11x+15 = 180

subtract 15 from each side

11x = 165

divide by 11

x = 15

<rsu = 8x+18

      = 8*15+18 = 138

< ust = 3x-3

    = 3*15-3 = 42

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47. A figure has an area of 50 units2. What will the new perimeter be after a dilation with a scale factor of 3?
Lesechka [4]

Answer:

150

Step-by-step explanation:

4 0
3 years ago
Question 3
Lunna [17]
Don’t click on that link
5 0
3 years ago
Compute the mean and variance of the following probability distribution. (Round your answers to 2 decimal places.) x P(x) 6 0.10
irinina [24]

Answer:

Mean = 16.5

Variance = 35.55

Step-by-step explanation:

 <u>          x      P(x)        x. P(x)     x²            x². P(x)</u>

          6      0.10          0.6      36            3.6

         12     0.35          4.2       144           50.4

        18     0.25           4.5       324            81

<u>         24     0.30          7.2        576         172.8</u>

                  ∑x P (x)  16.5         ∑x² P (x) 307.8

The expected value of x E[X] gives the mean where X is the discrete random variable with the given probabilities.

Mean is given by  E(X)=  ∑x P (x) =  16.5

Similarly the variance is also calculated using the expected value of X and X².

Variance is given= E(X)²-  [E(X)]²= 307.8- (16.5)²=  307.8-272.25 = 35.55

6 0
3 years ago
Mr. Harris ran 2 miles in 14.5 minutes. Ms. Mullen ran 2.5 miles in 16 minutes. Ms. Hubbard ran 3.5 miles in 24 minutes.
Masja [62]

Answer:

A. Ms harris was the fastest considering she finished 2.5 miles under 14.5 minutes

Step-by-step explanation:

7 0
3 years ago
(a) Find the slope of the curve y= x^2 - 2x - 3 at the point ​P(2​,​ -3) by finding the limit of the secant slopes through point
gayaneshka [121]

Answer:

Step-by-step explanation:

P=(2,-3)

Q=(a,a²-2a-3)

\Delta y=a^2-2a-3-(-3)=a^2-2a\\\Delta x=a-2\\\\\displaystyle \lim_{a \to 2} \dfrac{a^2-2a-3-(-3)}{a-2}  \\\\=\lim_{a \to 2} \dfrac{a^2-2a}{a-2}  \\\\=\lim_{a \to 2} \dfrac{a(a-2)}{a-2}  \\\\=\lim_{a \to 2} \dfrac{a}{1}  \\\\=\lim_{a \to 2} a  \\\\=2\\

Proof:

y'=(x²-2x-3)'=2x-2

y'(2)=2*2-2=2

7 0
3 years ago
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