?
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Answer:
Step-by-step explanation:
Given:
Number of eclairs = 3
Number of humbugs = 
Number of mints = 
Therefore, total number of sweets in the jar is,
Now, probability of selecting a sweet to be humbug is given as:
Therefore, the probability that it is a humbug is .
Answer:
a) All of them are out of charge = 9.31x10⁻¹⁰
b) 20% of them are out of charge = 5.529x10⁻⁴
Step-by-step explanation:
This problem can be modeled as a binomial distribution since
There are n repeated trials and all of them are independent of each other.
There are only two possibilities: battery is out of charge and battery is not out of charge.
The probability of success does not change with trial to trial.
Since it is given that it is equally likely for the battery to be out of charge or not out of charge so probability of success is 50% or 0.50
P = 0.50
1 - P = 0.50
a) All of them are out of charge?
Probability = nCx * P^x * (1 - P)^n-x
Probability = ₃₀C₃₀(0.50)³⁰(0.50)⁰
Probability = 9.31x10⁻¹⁰
b) 20% of them are out of charge?
0.20*30 = 6 batteries are out of charge
Probability =₃₀C₆(0.50)²⁴(0.50)⁶
Probability = 5.529x10⁻⁴
Convert 15% into a decimal. (0.15) Then multiply that by 550.
Answer:
<h2>x = 1</h2>
Step-by-step explanation:
Look a t the picture.
The triangles on the picture are similar.
Therefore the sides are in proportion:
<em>cross multiply</em>
<em>divide both sides by 40</em>
