All categories

3 years ago

What equation is parallel to the line 3x+y=5

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

3 0

Answer:

Any equation with the slope -3 and a y intercept that does not equal 5

Step-by-step explanation:

a line is parallel if the line have the same slope, and different y intercepts

3x+y=5

in slope intercept form is

y=-3x+5

slope : -3

y intercept 5

You might be interested in

Pls help me with this question!!!

yarga [219]

<h3>In which language u will speak...</h3>

6 0

3 years ago

Scienceeee pleaseeee helppp meee

Alexxandr [17]

Answer: Organic waste and toxic industrial waste

Step-by-step explanation: look it up if u dont believe me

6 0

3 years ago

Read 2 more answers

What is the equation in point-slope form of a line that passes through the points (5, −3) and (−2, 9 answer a. y−3=−127(x+5) b.

jeka94

The answer is
<span>b. y+3=−2(x−5)</span>

8 0

4 years ago

Read 2 more answers

Please please help what is pi rounded to the nearest hundredth

skad [1K]

The answer to this question is c

4 0

4 years ago

Read 2 more answers

The Skittles jar has a radius of 3.5 cm and a height of 11.5 cm. Using the two given boxes for reference what would be a good es

nevsk [136]

Answer:

1052

Step-by-step explanation:

The two given boxes for reference are presented below.

Since we know the dimensions of the first container, we can calculate its volume.

$V_1= 5 \text{cm} \cdot 4 \text{cm} \cdot 4 \text{cm} = 80 \text{cm}^3$

The first container held 192 skittles. Using that fact, now that we know the volume of the first box, we can calculate the volume of a single skittle.

$v = \frac{80}{192} = 0.416 \approx 0.42 \text{cm}^3$

The second container held 258 skittles.

The volume of the second box is:

$V_2 = 12 \text{cm}\cdot 3 \text{cm} \cdot 3 \text{cm} = 108 \text{cm}^3$

Using this facts, the volume of a single skittle would be

$v = \frac{108}{258} = 0.418 \approx 0.42 \text{cm}^3$

Therefore, the volume of single skittle is around to 0.42 cm³.

A skittle jar is a cylinder. Its volume is calculated by the formula

$V = r^2h \pi$ ,

where $r$ is the radius and $h$ is the height. From the given data, we have $r = 3.15 \text{cm}$ and $h = 11.5 \text{cm}$ . Hence, the volume of the jar is

$V = 3.5^2 \cdot 11.5 \cdot 3.14 = 442 \text{cm}^3$

Now, we can determine the number of skittles in the jar. Let $n$ be the number of skittles in the jar. Then,

$n = \frac{\text{volume of the jar}}{\text{volume of a skittle}} = \frac{V}{v} = \frac{442}{0.42} = 1052.38 \approx 1052\\$

4 0

3 years ago