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AlladinOne [14]
3 years ago
9

HELP PLEASE ASAP!!! Khan Academy unit test!

Mathematics
1 answer:
dsp733 years ago
4 0

Answer:

As=0.13

Step-by-step explanation:

If we have central angle we use this rule to find area of sector :

As=\pi r^{2}(\frac{C}{360})

C is central angle. r is radius.

As=\pi *9*\frac{\frac{9\pi }{17} }{360} =\\\\As=\pi *9*\frac{9\pi }{17*360} =\\\\

Evaluate :

\frac{798.63}{6120}=0.13

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Adding which of the following ordered pairs to the set [(0, 1), (2, 4), (3,5)) would make it not a function?
Kitty [74]

Answer:

(0,7)

Step-by-step explanation:

For a set of ordered pairs to be a function, there needs to be "ONE" value of y for each unique x value.

Thus, we see that the 3 ordered pairs given have x values of 0, 2, and 3.

Now, we look in the answer choices and find which ones are 0, 2, or 3 in x-coordinate.

That would be only (0,7). Now the original set has x = 0 corresponding to y = 1

Is that true for (0,7)?? NO!

x = 0 will now correspond to "TWO" values of y.

THis will make this NOT A FUNCTION.

So, (0,7) is correct.

3 0
3 years ago
Write the expression n n n n n n using an exponent. Name the base and the exponent.​
fiasKO [112]

Answer:

n⁶

Step-by-step explanation:

Base= n

exponent=⁶

8 0
3 years ago
Find the area of a regular octagon with side lengths of 17.2 m and an apothem length of 20.8 m.
jek_recluse [69]

Answer:

Pentagon a = 4.9 in. s = 7.1 in. /l ;/ >cvr'-. ~ j-?.1· '19~~. 5) Octagon a = 20.8 m s= 17.2m. ,4 ~;.>a-rt. ::: i, 17. z • t~f "g. ~ :::::, l'/?1 ,0 nt z, ... What is the length of the apothem to the nearest whole number

Step-by-step explanation:

Pentagon a = 4.9 in. s = 7.1 in. /l ;/ >cvr'-. ~ j-?.1· '19~~. 5) Octagon a = 20.8 m s= 17.2m. ,4 ~;.>a-rt. ::: i, 17. z • t~f "g. ~ :::::, l'/?1 ,0 nt z, ... What is the length of the apothem to the nearest whole number

5 0
3 years ago
PLEASE HELP ASAP Due in 1 day!!!
Helen [10]

Step-by-step explanation:

Q1 . (f+g)(x) = f(x) + g(x)

=4x-4 +2x^2 -3x

= 2x^2 + x -4

Q2. (f-g)(x) = f(x) - g(x)

= 2x^2−2 - (4x+1)

= 2x^2 -2 -4x -1

= 2x^2 - 4x -3

Q3. h(x)=3x−3 and g(x)=x^2+3

(h.g)(x) = h(x) × g(x)

= (3x-3) × (x^2 + 3)

=3x^3 -3x^2 + 9x -9

Q4.f(x)=x+4 and g(x)=x+6

(f/g)(x) = f(x) ÷ g(x)

= x+4 / x+6

the domain restriction is x>-6

x<-6

x doesn't equal (-6)

7 0
3 years ago
What equation is equivalent to 2(4x+3)-5x=1
matrenka [14]
8x+6-5x=1

3x+6=1

please vote my answer branliest. Thanks.
8 0
3 years ago
Read 2 more answers
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