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Keith_Richards [23]
3 years ago
14

A courier service advertises that its average delivery time is less than six hours for local deliveries. A random sample of size

10 of the amount of time this courier takes to deliver packages to an address across town was taken. The true standard deviation is not known. A hypothesis test will be run to determine if there is sufficient evidence to support the courier's advertised claim. What case is best
Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
3 0

Answer, Step-by-step explanation:

According to the exercise, we evaluate the delivery time of a courier company and we will hypothesize the best case with a sample size of 10, which is:

Small sample T test for single mean

The hypothesis that we will develop will be the following:

null hypothesis = mu> = 6

hypothesis alternativa: <6

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Answer:

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Step-by-step explanation:

Given

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Required

Determine the equivalent expression

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Simplify the first fraction

\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Apply law of indices on the first fraction;

5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}

\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}

Apply law of indices:

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Evaluate the bracket

5q^5w^4*4 * q^{12} * w^{5}

Collect Like Terms

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Hence:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

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