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Jobisdone [24]
3 years ago
13

a cylinder shaped barrel has a diameter of 3 feet and a height of 4.5 feet if the barrel is empty approximately how much water i

s needed to fill the barrel and I need work to be shown please and thank you

Mathematics
1 answer:
pav-90 [236]3 years ago
6 0
Volume of Cylindar:
v = \pi {r}^{2} h
the radius is half of the diameter

v = \pi {1.5}^{2} 4.5
v = 31.8

Option A.) 32 cu. ft.
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Shtirlitz [24]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
You have a pool that measures 8 yards by 10 yards. You want to build a deck around all four sides of the pool and you want to in
gladu [14]
Given:
pool length : 10 yards
pool width : 8 yards

Area = 10 yds * 8 yds = 80 yd²

(10 + 2x)(8 + 2x) = 120 
10(8 + 2x) + 2x(8+2x) = 120
80 + 20x + 16x + 4x² = 120
4x² + 36x + 80 - 120 = 0
4x² + 36x - 40 = 0
4(x² + 9x - 10) = 0
4(x + 10)(x - 1) = 0

x + 10 = 0
x = -10
x - 1 = 0 
x = 1

the width of the deck is 1 yard


7 0
3 years ago
Part 3: The Space Inside! Find the volume of the shipping box using the two methods and show your work: Packing cubes Using the
kirill115 [55]

Answer:shipping box=3.75*3*3.25=36.562 cubic feet.in width we have 15 cubes,in the legnt 12 while in height 13.with a total of 2340 cubes

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
4. Solve the inequality.<br>​
olga2289 [7]

Answer:

D

Step-by-step explanation:

Given

- 12 ≤ 2x - 4 < 10 ( add 4 to all 3 intervals )

- 8 ≤ 2x < 14 ( divide all 3 intervals by 2 )

- 4 ≤ x < 7

7 0
3 years ago
A rubber ball is dropped from the top of a hole. Exactly 20 seconds later, the sound of the rubber ball hitting bottom is heard.
gayaneshka [121]

9514 1404 393

Answer:

  4192.9 ft

Step-by-step explanation:

We assume your falling-distance formula is supposed to be ...

  s = 16t²

So, the time required to fall distance s is ...

  t = √(s/16) = (1/4)√s

The time required for sound to travel distance s is ...

  s = 1100t

  t = s/1100

Then the sum of the time for the ball to fall and the time for the sound to travel back is ...

  (1/4)√s + s/1100 = 20

  275√s = 22000 -s . . . . . multiply by 1100 and subtract s

  75625s = s^2 -44000s +484,000,000 . . . square both sides

  s^2 -119,625s +484,000,000 = 0 . . . . put in standard form

  s ≈ (1/2)(119,625 ±√12,374,140,625) = {4192.943, 115432.057}

Only the smaller of these two solutions makes any sense in this problem.

The hole is about 4192.9 feet deep.

_____

<em>Additional comment</em>

The distance equation for the falling object presumes a vacuum. The sound transmission presumes the presence of air, so the question setup is self-contradictory.

7 0
3 years ago
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