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Jobisdone [24]
3 years ago
13

a cylinder shaped barrel has a diameter of 3 feet and a height of 4.5 feet if the barrel is empty approximately how much water i

s needed to fill the barrel and I need work to be shown please and thank you

Mathematics
1 answer:
pav-90 [236]3 years ago
6 0
Volume of Cylindar:
v = \pi {r}^{2} h
the radius is half of the diameter

v = \pi {1.5}^{2} 4.5
v = 31.8

Option A.) 32 cu. ft.
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Barbara buys a box of pens for $4. for every additional box she buys, she gets a $1 discount. which expression represents the to
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Let b=the number of boxes, c=cost of the pens
The expression that represents the total cost of the pens if a box costs 4 dollars and then she gets a 1 dollar discount for every additional box is c(b)=3b+1. We got this from the original equation c(b)=4+(4-1)(b-1). Simplify this and you will get c(b)=3b+1. 
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Step-by-step explanation:

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According to a study in a medical journal, 202 of a sample of 5,990 middle-aged men had developed diabetes. It also found that m
tekilochka [14]

Answer:

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Has diabetes.

Event B: Is very active.

Probability of having diabetes:

To find this probability, we take in consideration that:

It also found that men who were very active (burning about 3,500 calories daily) were a fourth as likely to develop diabetes compared with men who were sedentary. Assume that one-fifth of all middle-aged men are very active, and the rest are classified as sedentary.

So the probability of developing diabetes is:

x of 4/5 = x of 0.8(not active)

x/4 = 0.25x of 1/5 = 0.2(very active). So

P(A) = 0.8x + 0.25*0.2x = 0.85x

Probability of developing diabetes while being very active:

0.25x of 0.2. So

P(A \cap B) = 0.25x*0.2 = 0.05x

What is the probability that a middle-aged man with diabetes is very active?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.05x}{0.85x} = \frac{0.05}{0.85} = 0.0588

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

4 0
3 years ago
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